search for: tylerdeanrudolph

In conducting studies of animal orientation and displacement, I need to produce circular histograms of angles (bearings in radians 0-2pi) where the centre of the circle indicates very few observations for a given bin of angles and outwardly concentric circles indicate greater frequencies of observations for a given bin of angles. I'd like not to have to write the function myself but I

http://r.789695.n4.nabble.com/file/n2287976/BBMM_BUG.RData BBMM_BUG.RData I've been constructing utilization distributions for 63 animal movement trajectories using a Brownian bridge movement model with BBMM. I started noticing after running the routine numerous times at different resolutions that certain UDs would be grossly wrong, meaning instead of returning a strongly negative

Is there any really easy way to truncate integers with several consecutive digits without rounding and without converting from numeric to character (using strsplit, etc.)?? Something along these lines: e.g. = 456 truncfun(e.g., location=1) = 4 truncfun(e.g., location=1:2) = 45 truncfun(e.g., location=2:3) = 56 truncfun(e.g., location=3) = 6 It's one thing using floor(x/100) to get 4 or

I've exceeded the maximum time I am willing to accept for solving simple problems so I thank all in advance for your assistance. I am trying to plot text combined with an object value and a superscript. obv = 5 text = "Population mean =" ss = ^o # degrees Something like this (very naive so you get the idea): expression(text, obv, ss) paste(text, obv) # works ...but of course I

I have a vector of unique elements that I want to replicate a variable number of times depending on the element (lengths all > 800). However I noticed that the resulting length was not the sum of the each argument. The following example demonstrates this. I am confused as to why this works: rep(1:4, c(2,1,2,1)) [1] 1 1 2 3 3 4 but this doesn't: rep(1:3, each=c(2,1,2)) [1] 1 1 2