Displaying 4 results from an estimated 4 matches for "trts".
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tres
2006 Mar 27
0
not a problem: a submission (PR#8714)
...plus)
plot(x=0,y=0,type="n",xlim=c(minx,maxx),ylim=c(miny,maxy),lab=c(2,4,0),xlab="month",ylab="Relative
Growth Rate",axes=FALSE)
axis(1,at=1:3,month.abb[1:3]) #axis(1,at=1:3,labels=c("Jan","Feb","Mar"))
has the
same effect
axis(2)
trts=c("T1","T2");syms=c(21,24)
for (i in 1:2) {
A=subset(RGR,treatment==trts[i])
points(x=A$xvals,y=A$yvals,pch=syms[i])
segments(A$xvals,A$yvals-A$errminus,A$xvals,A$yvals+A$errplus) #similar
to
symbols(x=A$xvals,y=A$yvals,boxplots=cbind(0,0,A$errminus,A$errplus,0.5),inch...
2003 Aug 14
1
gnls - Step halving....
...or the gnls fit was (using a 'difference
parameterization' like SAS):
options(contrasts=c("contr.SAS","contr.poly"))
VA1.gnls<-gnls(DRAM~SSlogis(MED,phi1,phi2,phi3),
data=VA1,params=list(phi1~TRAT,phi2~TRAT,phi3~TRAT),
start=c(
23.36209, ****avg of phi1 for the 10 trts *********
-0.854979000000004, ***** diff. between avg and nls
estimate of TRAT#2 ******
.....and so on
I´d appreciate any comment
Thanks
CM
2007 Jul 05
3
summarizing dataframe at variable/factor levels
All,
Is there an efficient way to apply say "mean" or "median" to a dataframe
according to say all combinations of two variables in the dataframe?
Below is a simple example and the outline of a "manual" solution that
will work but is not very efficient
(could also generalize this to a function). Searched the archives and
docs but didn't see anything close to
2005 Feb 23
2
data.frame error message
Dear R users,
I am using v2.0.1 on Windows 2000. I have read a ".dat" file with several
vectors, including 2 factors (2 levels x 3 levels), and a vector of
responses, into R. There are no unique row names. When I try plot(x,y) or
lm(y~x) the following error is returned:
Error in model.frame(formula, rownames,...extranames: variable lengths differ
What am I doing wrong? I am a