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Hello all, So I am using the (formula entry) method for randomForests: randomForest(y~x1+x2+...+x39+x40,data=xxx,...) but the issue is that some of the items in that package dont take a formula entry - you have to explicitly state the y and x vector: randomForest(x=xxx[,c('x1','x2',...,'x40')],y=xxx[,'y'],...) Now my question is whether there is a function/way

if i were to have a block size of 4 people and i want to assign a treatment combination to the entire block, there would be 16 different treatment combinations (TTTT, TTTP, TTPP, PTTP, etc.) i am trying to get all 16 permutations and i am able to use this code below. drugs=c('P','T'); comb=expand.grid(drugs,drugs,drugs,drugs) for a block size of 3 the code would be

Hello all, I what to print the banner plot that is output from the mona method in the cluster package but the problem is I dont want to print all that red ink. Here is an example: data(animals) ma <- mona(animals) ma ## Plot similar to Figure 10 in Struyf et al (1996) plot(ma) I can change the bar color by using the argument col=c(0,0) - plot(ma,col=c(0,0)) - but then the variable labels also

Hi all- this seems to be simple to figure out but since im new to writing functions I dont know what is happening. Here is my code along with the error I am receiving: semivario=function(data,ids,times,resids){ id=unique(data$ids) index=combinations(length(data$times[data$ids==id[1]]),2) time=gamma=numeric(dim(index)[1]) for (j in 1:dim(index)[1]){

...Sep 2011 16:14:05 -0400 > From: Jean-Christophe BOU?TT?<jcbouette at gmail.com> >> Hello, >> You can check ?model.frame. >> I do not know however to extract only the right-hand of left-hand > part >> of a formula. >> >> JC >> >> 2011/9/22 trekvana<trekvana at aol.com>: >>> Hello all, >>> >>> So I am using the (formula entry) method for randomForests: >>> >>> randomForest(y~x1+x2+...+x39+x40,data=xxx,...) but the issue is that > some of >>> the items in that package dont take a fo...