Displaying 1 result from an estimated 1 matches for "tp4466499p4466499".
2012 Mar 12
2
Maximum of remaining elements of vector
...)
the second one: max(x[2:length(x)])
the third one: max(x[3:length(x)]) and so on
Of course this can be done with a loop, but isn't there a nicer and faster
way to do so?
Regards,
bahave14
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