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14305907
2010 Nov 25
6
help: program efficiency
...ter way to do it?
nodup = function(t)
{
t.index=0
t.dup=duplicated(t)
for (i in 2:length(t))
{
if (t.dup[i]==T)
t.index=t.index+0.01
else t.index=0
t[i]=t[i]+t.index
}
return(t)
}
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