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...)-0.075) + return(F) + } > p0<-c(0.1,0.1,0.1) > dfsane(par=p0,fn=f,control=list(maxit=3000)) I have substituted estimated values for all the parameters into the above equations. Thanks -- View this message in context: http://www.nabble.com/Non-negative-solutions-to-complicated-equations-tp24622867p24622867.html Sent from the R help mailing list archive at Nabble.com.