search for: tp24495390p24495390

Displaying 1 result from an estimated 1 matches for "tp24495390p24495390".

2009 Jul 15
2
Problems with computing an aggregated score
...and C in the following: A (8+5+4)/3 = 5.67 B (6+5+4)/3 = 5 C (8+8+0)/3 = 5.33 Is there any way to do this? Any clues, hints and suggestions are highly appreciated, many thanks in advance Johannes -- View this message in context: http://www.nabble.com/Problems-with-computing-an-aggregated-score-tp24495390p24495390.html Sent from the R help mailing list archive at Nabble.com.