Displaying 1 result from an estimated 1 matches for "tp1565083p1565083".
2010 Feb 22
4
Normal distribution (Lillie.test())
...olmogorov-Smirnov) normality test
data: z
D = 0.0218, p-value = 0.0278
I read wiki, but still can understand it..
Can anyone, give an explanation of my output D and p-value?
Thanks in advance
Gr. Bosken
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