Displaying 1 result from an estimated 1 matches for "tp14370723p14370723".
2007 Dec 17
2
Must be obvious but not to me : problem with regular expression
...uot;
> s[grep(".P[^0]", s)]
[1] "cc.P1" "dd.P2"
It works !!!
Has someone an idea to solve this small problem ?
Thanks in advance,
Ptit Bleu.
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