search for: tolerance

...================================================================ Polyhedron Benchmark Validator Copyright (C) Polyhedron Software Ltd - 2004 - All rights reserved Test File : llvm_gfortran_lin_p4.run Instruction File : ../../f90valid.in > Value= 14159 Target= 14159 Tolerance= 0 > Value= 16 Target= 16 Tolerance= 0 > Value= 1000000 Target= 1000000 Tolerance= 0 > Value=0.44068679351 Target=0.44068679400 Tolerance=0.10000000000E-06 > Value= 10000 Target...

The floating-point expectations allow for an error tolerance. Is there any similar facility for dates? For example, say I have a custom class that handles date/time spans and I want to spec it: context "A DateRange span" do specify "should know when a week ago is :)" do d = DateRange.new d.last_week.should_be_close_to(1....

I am having a hard time understanding how to perform a "repeated measures" type of ANOVA with R. When reading the document found here: http://cran.r-project.org/doc/contrib/Lemon-kickstart/kr_repms.html I find that there is a reference to a function make.rm () that is supposed to rearrange a "one row per person" type of frame to a "one row per observation" type

Hi all, Could we modify the "%%" (modulo)-operator to include some tolerance for rounding-errors when supplied with doubles? It's not much work (patch supplied on the bottom), and I don't think it would break anything, only if you were really interested in analysing rounding differences. Any ideas about implementing this and overwriting base::`%%`, or would we wan...

I have written a function that goes through a database and calculates various metric scores and allocates them to a data set. For 400 of the 500 sites that I calculate these metrics for works fine and allocates the scores into the appropriate column. For some reason, some sites I run into the below problem: Here is what I am doing: > names(orig.metric) [1] "BenInsect"

...table use of $BLAS_LIBS ... OK * checking tests ... make[3]: Entering directory `/home/mfa/gilp/toolchain/R/src/R-rc/tests/stats.Rcheck/tests' Running 'nafns.R' Running 'nls.R' Comparing 'nls.Rout' to 'nls.Rout.save' ...134c134 < Achieved convergence tolerance: 2.75e-06 --- > Achieved convergence tolerance: 2.74e-06 145c145 < 3: 0.00060639084: 0.00517051 0.999153 --- > 3: 0.00060639084: 0.00517052 0.999153 214c214 < Achieved convergence tolerance: 1.04e-07 --- > Achieved convergence tolerance: 1.34e-07 249c249 < Achieved converge...

...have to add a spline to my longitudinal spaghetti plot. I have the plot, but I can't add the spline, a overall trend line. In the SAS code they use the command 'I=SM50S' and I would prefer something similar. I?m using R 2.10.1 on windows XP? I have made this working example. tolerance.pp <- read.table("http://www.ats.ucla.edu/stat/R/examples/alda/tolerance1_pp.txt ", sep=",", header=T) # install.packages("lattice", dep = T) library(lattice) xyplot(tolerance ~ age, groups = id, data=tolerance.pp, type = "l") This is where I want to add...

...cited rounding behind the scenes. Best wishes, Frederick On Tue, Sep 11, 2018 at 12:11:29PM -0400, Duncan Murdoch wrote: > On 11/09/2018 11:23 AM, Emil Bode wrote: > > Hi all, > > > > > > > > Could we modify the "%%" (modulo)-operator to include some tolerance for rounding-errors when supplied with doubles? > > > > It's not much work (patch supplied on the bottom), and I don't think it would break anything, only if you were really interested in analysing rounding differences. > > > > Any ideas about implementing this and...

Dear list, I am from an engineering background, accustomed to work with tolerances. For example, I have measured Q = 0.15 +- 0.01 m^3/s H = 10 +- 0.1 m and now I want to calculate P = 5 * Q * H and get a value with a tolerance +- What is the elegant way of doing this in R? Thank you, Jan

Hi, Try either: tolerance <- read.csv("http://www.ats.ucla.edu/stat/r/examples/alda/data/tolerance1.txt") ?aggregate(exposure~male,data=tolerance,mean) ?# male exposure #1??? 0 1.246667 #2??? 1 1.120000 #or ?library(plyr) ?ddply(tolerance,.(male),summarize,exposure=mean(exposure)) #? male exposure #1??? 0 1.2...

...act=on >> > -Ofast -ffp-contract=off >> >> Let's separate completely FP-contract and fast-math. They're >> different >> things and need different solutions. >> >> >> > if(TEST_SUITE_USES_FAST_MATH) >> > add_definitions(-DFP_ABSTOLERANCE=1e0) >> > else() >> > add_definitions(-DFP_ABSTOLERANCE=1e-5) >> > endif() >> >> This doesn't make sense. If my program decreased precision by 5 >> orders >> of magnitude with -ffast-math, I'd be *very* worried. > > Is this an absol...

On 11/09/2018 11:23 AM, Emil Bode wrote: > Hi all, > > > > Could we modify the "%%" (modulo)-operator to include some tolerance for rounding-errors when supplied with doubles? > > It's not much work (patch supplied on the bottom), and I don't think it would break anything, only if you were really interested in analysing rounding differences. > > Any ideas about implementing this and overwriting base::`...

Dear R Users and Developers, I am trying to do the equivalent of v <- c(1,2,3,3,2,1,) vu <- unique(v) for a vector such as v2 <- c(1.02, 2.03, 1.00, 3.04, 3.06) vut <- ... As indicated in the subject, we need approximately unique values with a defined tolerance, i.e. for the v2 vector the resulting vut vector using a tolerance of .1 should return e.g. [1] 1.02 2.03 3.06 Also, mean/min values instead of max could be returned. My actual question: Is there a convenience function or other mechanism already implemented that could do something similar? Than...

Have used Centos 5 now couple of weeks and started to find pieces on places, ie. found logs :D Now, these ntpd errors strances me. Anyone else getting these? Errors frequency error 500 PPM exceeds tolerance 500 PPM: 1 time(s) frequency error 503 PPM exceeds tolerance 500 PPM: 1 time(s) frequency error 504 PPM exceeds tolerance 500 PPM: 1 time(s) frequency error 505 PPM exceeds tolerance 500 PPM: 1 time(s) frequency error 509 PPM exceeds tolerance 500 PPM: 3 time(s) frequency error 512 P...

Dear All I am using rgenoud to solve the following maximization problem: myfunc <- function(x) { x1 <- x[1] x2 <- x[2] if (x1^2+x2^2 > 1) return(-9999999) else x1+x2 } genoud(myfunc, nvars=2, Domains=rbind(c(0,1),c(0,1)),max=TRUE,boundary.enforcement=2,solution.tolerance=0.000001) How can one increase the precision of the solution $par [1] 0.7072442 0.7069694 ? I have tried solution.tolerance but without a significant improvement. Any ideas? Thanks in advance, Paul

I have a longitudinal data set in long format and I want to run individual regressions. I do this by using the by() function as follows: temp <- by(tolerance.pp, tolerance.pp$id, function(x) summary(lm(tolerance ~ time, data=x))) This works fine. Coefficients for the first two subjects are shown below. Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 1.9020 0.2519 7.549 0.00482 ** time 0.1190...

I have two Internet connections which connected to different ISP. one is for normal usage , 2nd one is for backup fault tolerance how do I implement fault tolerence multiple internet connections in shorewall ?

Dear list, How is the tolerance for a model parameter in an lm() call extracted? I did not see a solution in the documentation for lm(), or predict(), nor in the archives using 'tolerance' as the search string. I also checked into the nlme package, though nothing popped out at me. Sincerely, KeithC.

...o did traceback() which just took me to the function listed in the error message. I can't determine where the NA/NaN/Inf is (are) coming from. Any help would be appreciated. I am using Rwin 1.8.1 (pre-compiled) on Win2000 Professional. Thanks, Dan Nordlund ## toy problem library(nlme) tolerance.pp <- as.data.frame( matrix(c( 9,11,2.23, 9,12,1.79, 9,13,1.90, 9,14,2.12, 9,15,2.66, 45,11,1.12, 45,12,1.45, 45,13,1.45, 45,14,1.45, 45,15,1.99, 268,11,1.45, 268,12,1.34, 268,13,1.99, 268,14,1.79, 268,15,1.34, 314,11,1.22, 314,12,1.22, 314,13,1.55, 314,14,1.12, 314,15,1.12 ), byrow = T, ncol...

...hypothetical data for simplification. for example I have : table 1 table 1: species occurance data speciesX speciesY speciesZ speciesXX Plot1 1 0 1 0 Plot2 0 1 1 0 Plot3 0 0 0 1 Plot4 1 0 1 0 Table 2 table 2. species tolerance data EnviA EnviB EnviC speciesX 0.21 0.4 0.17 speciesY 0.1 0.15 0.18 speciesXX 0.14 0.16 0.19 You may noticed that table 2 does not have species Z which was in table 1. Now I want to get the average value of species tolerance in each plot based on...