Displaying 3 results from an estimated 3 matches for "times3".
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times
2005 Jan 26
2
reshape (a better way)
...1, varying2,etc,... and each are
assosiated with their own times1, times2.
something like
reshape(mydata, direction="long", varying1=varying1,varying2=varying2,
varying3=varying3, split=list(regexp="[a-z][0-9]", include=TRUE),
idvar="ID", times1=times1, times2=times2, times3=times3)
Jean
2006 Aug 26
1
problems with loop
...Model_1=function(beta0_mod,mu_mod,k_mod,I_mod)
{
parms = c(beta0=beta0_mod, mu=mu_mod, k=k_mod)
my.atol = 1e-6
times1=c(0,0.002884615,0.003846154,0.005769231,0.009615385,0.01,0.019230769)
times2=c(0.028846154,0.038461538,0.057692308,
0.076923077,0.083333333,0.096153846)
times3=c(0.115384615,0.125,0.134615385,0.166666667,0.25,0.416666667,0.5)
times4=c(0.58333333,0.666666667,0.75,0.83333333,0.916666667,1)
times5=c( 1.166666667,1.25,1.5,1.6,1.75,2,2.5)
times6=seq(3,20)
times = c(times1,times2,times3,times4,times5,times6)
ODE_sys = functio...
2007 Jan 19
4
Newbie question: Statistical functions (e.g., mean, sd) in a "transform" statement?
Greetings listeRs -
Given a data frame such as
times
time1 time2 time3 time4
1 70.408543 48.92378 7.399605 95.93050
2 17.231940 27.48530 82.962916 10.20619
3 20.279220 10.33575 66.209290 30.71846
4 NA 53.31993 12.398237 35.65782
5 9.295965 NA 48.929201 NA
6 63.966518 42.16304 1.777342 NA
one can use "transform" to