search for: this_addr

...integral part of the Instruction. You can change it by > providing a name when you create the instruction. Following your hint, can I understand in this following way? The name (denoted by "<result>") is actually a referrer to the instruction . Consider this instruction: %this_addr = alloca %struct.String* ; <%struct.String**> [#uses=4] Here "%this_addr" (which is not a argument) is actually a string. Am I right? And this name is recorded in the symbol table of a module. In case that an instruction does not have a name, what then happens? I mea...

...tion.  You can change it by >> providing a name when you create the instruction. > > Following your hint, can I understand in this following way? > > The name (denoted by "<result>") is actually a referrer to the instruction . > Consider this instruction: >  %this_addr = alloca %struct.String*             ; <%struct.String**> [#uses=4] > Here "%this_addr" (which is not a argument) is actually a string. > Am I right? More or less. %this_addr is a pointer to a stack slot which contains a pointer to something of type struct.String. The typic...

Hi all, In the language specifications, many instructions have this form: <result> = ... So, where is "<result>" defined? Is it an integral part of an instruction? Consider the "getelementptr" instruction: <result> = getelementptr <pty>* <ptrval>{, <ty> <idx>}* How is the "<result>" represented? Best,

Yes, it's an integral part of the Instruction. You can change it by providing a name when you create the instruction. Reid On Thu, Jun 10, 2010 at 8:34 AM, Xiaolong Tang <xiaolong.snake at gmail.com> wrote: > Hi all, > > In the language specifications, many instructions have this form: > >  <result> = ... > > So, where is "<result>" defined?