search for: tf2715472

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2006 Nov 28
0
pivot algorithm
...for(g in j:100) {x[g]=xn[g] ; y[g]=yn[g]} z=c(x,y) dim(z)=c(100,2) z maybe the right solution would be to use intersection() but I couldnt figure out how to make it work. Any advice would be appreciated. Thanks Seth Latimer -- View this message in context: http://www.nabble.com/pivot-algorithm-tf2715472.html#a7571334 Sent from the R help mailing list archive at Nabble.com.