search for: testlme

...3 13 -0.842322442 1 1 4 14 -0.657256158 2 1 4 15 1.504491575 3 1 4 16 2.896007045 4 1 4 17 0.990505440 1 1 5 18 2.722942793 2 1 5 19 4.395861278 3 1 5 20 4.849296475 4 1 5 21 3.049616421 1 1 6 22 2.874405962 2 1 6 23 4.359511097 3 1 6 24 6.165419699 4 1 6 This happened: > testLME <- lme(Y~t+D,data=simpledata,random=~1|ID) > predict(testLME, simpledata[1,]) Error in val[revOrder, level + 1] : incorrect number of dimensions This has occurred with other datasets as well. Is this a bug in the code, or am I doing something wrong? (Also, is there a way to parse a formula...

In an attempt to learn to use the rv package, I have been working through the examples in Jouni Kerman and Andrew Gelman's "Using Random Variables to Manipulate and Summarize Simulations in R" (July 4, 2007). I am using a Dell Precision 380n computer running Gentoo Linux and R 2.2.1 (the latest available through Gentoo's portage/emerge system). Everything worked well until I

Hello, How would you go about handling the following situation? This is on R 2.12.0 on Ubuntu 32-bit. I have a wrapper function to lm. I want to pass in a subset argument. First, I just thought I'd use "...". ## make example reproducible set.seed(123) df1 <- data.frame(age = rnorm(100, 50, 10), bmi = rnorm(100, 30, sd = 2)) ## create a wrapper using

How is exact pattern matching achieved in GREP (and GREPlike) functions ? # Want: listing of all object names that end in *.lm > objects(pattern="*.lm",pos=1) # ... but get: all objects that partially match *.lm, e.g., *.lme [1] "j3.lm" "J3.lme" "j8.lm" "J8.lme" # Want: position of string "4jan2002" in vector >

I want to take the first row of each unique ID value from a data frame. For instance > ddTable <- data.frame(Id=c(1,1,2,2),name=c("Paul","Joe","Bob","Larry")) I want a dataset that is Id Name 1 Paul 2 Bob > unique(ddTable) Will give me all 4 rows, and > unique(ddTable$Id) Will give me c(1,2), but not accompanied by the name column.