Displaying 2 results from an estimated 2 matches for "tempdub".
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2010 Mar 22
1
Factors attribute format
...he response is a function of one or more of the dependent variables then of course it will be something other that a row of zeros. So far OK?
My problem in understanding comes with using a formula that contains R factors. I am using the following (from the TSA package) for an example:
l <- lm(tempdub ~ season(tempdub))
attr(l$terms, "factors")
season(tempdub)
tempdub 0
season(tempdub) 1
The function 'season' produces a factor (in this case with 12 levels, one for each month). But the factor attribute still has a '1'...
2012 Aug 19
2
Prueba de Thom y series temporales homogéneas de prueba
...1949 1950 1951 1952 1954 3465 3614
pdThom(as.vector(Adra.radiacion.diaria)[12:824])
# [1] 22.63508
which(is.na(as.vector(Almeria.radiacion.diaria)))
# [1] 886 1838 3221 3222 3223 3224 3227 3402 3470 3592 3693
pdThom(as.vector(Almeria.radiacion.diaria)[1839:3220])
# [1] 28.201
library(TSA)
data(tempdub)
pdThom(tempdub)
# [1] 8.195372
data(larain)
pdThom(larain)
# [1] 0.4683109
------------------- Fin del código R -----------
Como veis la única serie que «pasa» la prueba de Thom es la de lluvia en
Los Angeles del paquete TSA, pero estoy desorientado, no me lo creo.
¿Que opináis?
Gracias por ad...