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au_j
2001 Oct 17
3
Type III sums of squares.
...ly want a ***weighted***
average, with the weights corresponding to the preponderance of
the levels of B in the population.)
Note that if there is no interaction (if the gamma_ij are all zero)
then the hypothesis being tested is that for each fixed j, the mu_ij
are all ***identical*** (say mu_ij = tau_j) and hence the averages
over j are equal (mu_i.-bar = tau.-bar, independent of i.)
This is all easier to think about graphically. For each j, plot the
mu_ij against the index i, giving a ``profile''. ``No interaction''
means that all profiles are parallel. No interaction and no...