Displaying 11 results from an estimated 11 matches for "tagmarie".
2012 Sep 26
2
average environmental data if AnimalID and Time is duplicated
...or this timestamp to get a
data frame without duplicated Times and the respective average Temp and
Hunger.
I tried something like
Meanframe<- by(myframe[, 3:4], duplicated(myframe$ID,
Zusatzdaten3$Timestamp) == TRUE, mean)
but it doesn't work and I guess that it is also totally crap ;-)
Tagmarie
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2012 Sep 17
6
count NAs per week
Even though I work with R since a year or so I still struggle with simple
problems. I hope someone can help me with this. Been trying for days and am
a little frustrated now.
I have a data frame somewhat like the one bellow:
dattrial<-data.frame(a=c(1,NA,rnorm(4,10)), Week=c(3,3,3,4,4,4))
I want to know how many NAs I have in week 3 and in week 4.
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2012 Nov 27
5
loop with date
Hello,
I tried to construct my very first loop today and completly failed :-(
Maybe someone can help me?
I have a dataframe somewhat like this one:
myframe <- data.frame (Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00",
"24.09.2012 11:00",
"25.09.2012 09:00", "25.09.2012 10:00",
"25.09.2012
2012 Nov 09
3
if between 500-600 give 550
I have a data frame somewhat like this:
myframe <- data.frame (ID=c(2,3,4,5), Hunger =c(415,452,550,318 ))
myframe
Now I would like to add a column to the right which summarizes the values
for Hunger somewhat to reduce the number of values: If the values for Hunger
are between
300-400 I would like to insert the number 350,
between
400-500 insert 450
between
500-600 insert 550
Does
2012 Oct 26
0
mean of a value of the last 2 hours using plyr (Thank you)
Hi dear three helpers,
Thanks a lot! Your solutions worked great. Again I learned a lot.
Tagmarie
Am 25.10.2012 18:36, schrieb Felipe Carrillo:
> Another option using plyr,
> library(plyr)
> myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert",
> "Bert"), Timestamp=c("24.09.2012 09:00", "...
2012 Oct 25
2
mean of a value of the last 2 hours
Hello,
I have a data frame somewhat like that:
myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert",
"Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012
11:00"), Hunger=c(1,1,1,2,2,1) )
myframestime <- as.POSIXct (strptime(as.character(myframe$Timestamp),
2017 Aug 19
4
My very first loop!! I failed. May I have some start-up aid?
...good example. Sorry about that.
But I guess you know what I mean.
# Because I wish to run the functions three times I do want a data frame
(or matrix) in the end, which includes the results (kernel areas): That
means 12 columns and the three lines.
# How do I do that?
Many thanks in advance,
Tagmarie
2017 Aug 19
0
My very first loop!! I failed. May I have some start-up aid?
...ou know what I mean.
>
> # Because I wish to run the functions three times I do want a data frame (or
> matrix) in the end, which includes the results (kernel areas): That means 12
> columns and the three lines.
>
> # How do I do that?
>
> Many thanks in advance,
>
> Tagmarie
>
> ______________________________________________
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> and provide commented, minimal,...
2012 Jun 16
3
count data without NA in certain time intervals and plot it
Hello,
I'm quite new to R and still spend hours trying to figure out single things
so I hope nobody rolls his eyes over my question.
I have a data set over time and converted it to the POSTIXct format. I added
a column in the data set for the week and the month.
I try to get a plot which shows the weeks on the x-axis and the number of
datasets without NAs on the y-axis. That doesn't
2012 Dec 07
0
apply a function at: dateX, dateX+1, dateX+2, ....
...mberand the
# home range for the timespan 25. to 26. September. Each day is included
several times in the calculations.
# It would be easy to do for the example above by hand (subset) but not for
my dataset including a whole year.
# does anyone know how to do that?
# It would be very helpful!
Tagmarie
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2012 Dec 17
2
calculate a "rolling mean" including standard deviation
Hello everyone,
I have a data frame somewhat like this one:
myframe <- data.frame (Timestamp=c( "24.09.2012 06:00", "24.09.2012 07:00",
"24.09.2012 08:00",
"24.09.2012 09:00", "24.09.2012 10:00",
"24.09.2012 11:00",
"24.09.2012 12:00",