Displaying 1 result from an estimated 1 matches for "tablename1".
Did you mean:
tablename
2011 Jun 02
1
Help in a project
...--|------------------|------------------
1 | 10000 | NA
2 | NA | A
3 | 631 | NA
please note | represents another column.
this is for a large data set and I cannot manually go through this:
my attempt to this was :
l=0 # placeholder
m<-c() #newvariable 1
v<-c() #newvariable flag
for (z in tablename1$Variable_1)
(if (is.numeric(z) ) m[z:l] l=l+1 else v[z:1] l=l+1
Can you please guide me as to how to approach this problem?
Any help would be greatly appreciated.
Tarun Manchanda
[[alternative HTML version deleted]]