Displaying 5 results from an estimated 5 matches for "t04".
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04
2010 Aug 18
2
combinations
...iate any suggestions on which function to use to write subsequent functions analysing combinations of treatments.
This refers to experimental trials of medical treatments. I want to write routines to analyse various comparisons (combinations)
So .... if 5 treatments are available (t01, t02, t03, t04 and t05) I want to write a general routine that works out all possible combinations, without repeats. The other complication is that I want to be able to designate any one of the treatments as the common comparator such that all other treatments are compared to it.
For example, if I designate t04...
2011 Feb 20
2
concatenate vector after strsplit()
...reated by strsplit()
I want to concatenate the 1st 4 character elements of each list item as a new vector called file. I admit to being confused about list syntax even after numerous readings.
Here's what I tried:
ls <- list(c("Focused", "10k", "A12", "t04.tif", "+", "µm"), c("Focused",
"10k", "A12", "t08.tif", "+", "µm"), c("Focused", "10k", "A12",
"t12.tif", "+", "µm"), c("Focused", "10k&q...
2012 Oct 19
4
Creating a new by variable in a dataframe
Hello,
I have a dataframe w/ 3 variables of interest: transaction,date(tdate) &
time(event_tim).
How could I create a 4th variable (last_trans) that would flag the last
transaction of the day for each day?
In SAS I use:
proc sort data=all6;
by tdate event_tim;
run;
/*Create last transaction flag per day*/
data all6;
set all6;
by tdate event_tim;
last_trans=last.tdate;
Thanks
2006 Jan 15
2
rsync of file list
Hi All,
I would to rsync data spread of many files from remote site. Each file
may exist in total different location - the path for each file may be
different.
My question is:
Can I do it one single rsync command, giving a file containing list of
paths as parameter, or do I need to run rsync for each file.
I did not find any option doing it in the man page. I tried to play with
2010 Jul 23
2
start and end times to yes/no in certain intervall
Hi List,
I have start and end times of events
structure(list(start = c("15:00", "15:00", "15:00", "11:00",
"14:00", "14:00", "15:00", "12:00", "12:00", "12:00", "12:00",
"12:00", "12:00", "12:00", "12:00", "12:00", "12:00",