Displaying 7 results from an estimated 7 matches for "svyquantile".
2010 Aug 18
1
svyquantile w/ svyby is returning an error
svymean w/ svyby is working for me...
> svyby(~visitcnt, ~agegrp3.f, svymean, design=svydes)
agegrp3.f visitcnt se.visitcnt
18-44 18-44 8.755552 0.4953235
45-64 45-64 10.131555 0.5347806
65+ 65+ 9.588802 0.4323629
svyquantile is working for me...
> svyquantile(~visitcnt, quantiles=c(.25, .5, .75), ties="rounded", design=svydes)
0.25 0.5 0.75
visitcnt 3.021468 6.039823 11.49518
svyquantile w/ svyby is bombing on me...
> svyby(~visitcnt, ~agegrp3.f, svyquantile, quantiles=c(.25, .5...
2009 Mar 11
1
CI from svyquantile in survey package
...version 2.8.1 (2008-12-22) and survey
package (3.11-2) on FC7 linux. To simplify my question I use an example from
that package:
R> data(api)
R> dclus1<-svydesign(id=~dnum, weights=~pw, data=apiclus1, fpc=~fpc)
R> (tst <- svyby(~api99, ~stype, dclus1, svyquantile,
quantiles=0.5,ci=TRUE))
stype api99 se
E E 615 37.89
H H 593 69.52
M M 611 37.67
R> str(tst)
Classes ???svyby??? and 'data.frame': 3 obs. of 3 variables:
$ stype: Factor w/ 3 levels "E","H","M": 1 2 3...
2010 Feb 18
1
survey package question
Should the svyby function be able to work with svyquantile? I get the
error below ...
data(api)
dclus1<-svydesign(id=~dnum, weights=~pw, data=apiclus1, fpc=~fpc)
svyby(~api00,
design=dclus1,
by = ~stype,
quantiles=c(.25,.5,.75),
FUN=svyquantile,
na.rm=T
)
> Error in object$coefficients : $ op...
2012 Oct 02
2
svyby and make.formula
Hello,
Although my R code for the svymean () and svyquantile () functions works fine, I am stuck with the svyby () and make.formula () functions. I got the following error messages.
- Error: object of type 'closure' is not subsettable # svyby ()
- Error in xx[[1]] : subscript out of bounds # make.formula ()
A reproducible example is...
2007 Dec 19
2
4 questions regarding hypothesis testing, survey package, ts on samples, plotting
Good morning!
I have 4 questions which trouble me:
1. I want to test the hypothesis that the 2 proportions (the mean of a binomial) which come from 2 different samples are equal. I want to use the following function
z= (p1-p2)/ sqrt((p1(1-p1)/n1)+(p2(1-p2)/n2)) which is one of the standard formulas for this case. Is there such a function in R?
p1=the proportion from the first sample
n1=the
2004 Apr 12
2
Complex sample variances
Hello,
Is there a way to get complex sample variances in the survey package on summary statistics other than means? If not, can they be added to a future version? It would be be great to have them on totals, quantiles, ratios, and tables (eg row percent, columns percent, etc).
Thanks.
Fred
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2010 May 21
1
viewing function code
Hi,
I want to view the code for the function confint in the stats package.
Typing just confint doesn't work. How can I view the code?
Thanks,
Walt
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