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...ll" survreg.distributions$weibull3p$dist <- "extreme" survreg.distributions$weibull3p$trans <- function(y, x0) log(y) + x0 survreg.distributions$weibull3p$dtrans <- function(y) 1/y survreg.distributions$weibull3p$itrans <- function(x, x0) exp(x-x0) I then get a failure by survregDtest(survreg.distributions$weibull3p) that x0 is missing (since the transformation function is expected to take only one argument). Any ideas? Or is there maybe a package somewhere that supports 3-parametric weibull regression which I missed? Regards, Andreas [[alternative HTML version deleted]]

I am trying to create a frequency distribution and I am a bit confused. Here are the commands I have entered: > data <- read.csv(file="40609_sortedfinal.csv",head=TRUE,sep=",") > NumberOfActionsByStatus = data$STATUS > NumberOfActionsByUser = data$ETS_LOGIN > NumberOfBidOffer = data$BID_OFFER > NumberOfActionsByUser.freq = table(NumberOfActionsByUser) >