Displaying 6 results from an estimated 6 matches for "survial".
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survival
2008 Mar 19
1
weibull model
Dear Helpers:
If you know how to fit a Weibull model using R, you
are my savior for my project. The hazard ramda is
specified as t^alpha * (1+a*dose*exp(-b*dose)).
Or, can we modify the Cox model to capture the
proportional part above? Here t is the survial time,
dose is a subject received in a exposed group.
Thank you a lot.
Boshao
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2006 Jan 17
2
help with parsing multiple coxph() results
...===============
The question I have are:
1. How do I access different parts of coxph result?
2. Is there a way to store multiple coxph results into a data structure that
can be efficiently accessed?
3. if I find a list of genes I am interested, are there efficient to plot
all of them based on the survial data?
Thanks
Hao Liu, Ph. D
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2011 Apr 13
3
Problem with dyn.load in R 2.13.0
I have a test directory for the survival suite, and dyn.load has ceased
to work in it. Below shows the log:
tmt1075% R --vanilla
R version 2.12.2 (2011-02-25)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: x86_64-unknown-linux-gnu (64-bit)
R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain
2004 Nov 10
1
worked in R, but not in S-Plus
...not in
S-Plus, can anyone suggest a solution?
> f.coxph.zph<-function(x)
{
cox.fit <- coxph(Surv(time.cox, status.cox) ~ x,
na.action = na.exclude, method = "breslow")
fit.zph<-cox.zph(cox.fit,transform='log')
fit.zph$table[,3]
}
yyy is my data frame that contains survial time,
censor status and predictor variables.
> time.cox<-yyy$time
> status.cox<-yyy$status
> apply(yyy[,-(1:2)],2,f.coxph.zph)
When run in S-Plus, it gave the following error
message:
Problem in model.frame.coxph(fit): Object "x" not
found
If I remove the 2nd and 3rd li...
2004 Nov 10
0
RE: [S] worked in R, but not in S-Plus
...not in
S-Plus, can anyone suggest a solution?
> f.coxph.zph<-function(x)
{
cox.fit <- coxph(Surv(time.cox, status.cox) ~ x,
na.action = na.exclude, method = "breslow")
fit.zph<-cox.zph(cox.fit,transform='log')
fit.zph$table[,3]
}
yyy is my data frame that contains survial time,
censor status and predictor variables.
> time.cox<-yyy$time
> status.cox<-yyy$status
> apply(yyy[,-(1:2)],2,f.coxph.zph)
When run in S-Plus, it gave the following error
message:
Problem in model.frame.coxph(fit): Object "x" not
found
If I remove the 2nd and 3rd li...
2006 Jan 17
0
help with coxph() for multiple genes
...I have are:
1. How do I access different parts of coxph result?
2. Is there a way to store multiple coxph results into a data
structure that can be efficiently accessed?
3. if I find a list of genes I am interested, are there efficient to
plot all of them based on the survial data?
Thanks
Hao Liu, Ph. D
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