search for: surfit

??? Both ?survit.object (linked in the see also section of ?survfit) and ?summary.survfit give you this information. Do you not know how to use R's help faciities -- in which case you should learn them now; see ?help -- or have I misunderstood your query? Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it."

Hi I am not sure hiw to get thr CI from summary function on the survfit object. I can get the percent survival for 2 years from survfit object but I dont get Confidence intervals Could anyone suggest a hint Thanks Adrian [[alternative HTML version deleted]]

Did you not notice the conf.type = "none" argument to your survfit call and the associated documentation in the survfit help? -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Aug 26, 2017 at 5:18 PM, Adrian Johnson

Dear Bert, thank you for suggestion. I am aware of R-help function. I must apologize, my earlier question could lead to assumptions otherwise. As you can see below, I only get Std. error but not lower and Upper CIs. I was wondering if there is another argument or method, could give CIs which I cannot find anywhere. Thanks Adrian > Nsurv <-

...es puntos; .- Pregunto si puedo sacar, aumentarle al summary también los siguientes puntos Intervalo de confianza, desviación estándar? .- como puedo obtener la correlación en variables dicotómicas ej. tau de kendall? .- Como puedo cambiar los títulos del ingles al español de los encabezados de un surfit(Surv(tiempo, estado))? -- Gracias, por existir comunidad. ernesto [[alternative HTML version deleted]]

Hi Fello: I am asked to compute the Kaplan-Meier estimator of data with right censoring without using surfit(). Does anyone know how to use R to compute the estimators? The data should input X: vector of right-censored observed time for n individuals, and d: vector of failure time indicators (0=censored individual;1=unconsored individual) and the function should return with t: vector of sorted observed ev...

...over time: > > leaves.cox <- coxph(Surv(time, censo) ~ treatment + species, data= wsuv) > > > When I plot 'survfitt(leaves.cox)', I come up with a survivor curve that > starts at 1 ends at 0.4. The problem is that at time 42 almost all > leaves are dead. I wander if surfit plot at time 42 should also be close > to zero? Yes, it probably should. It is a bit hard to tell what is going wrong, though. If you do plot(survfit(Surv(time,censo)~1,data=wsuv) plot(survfit(Surv(time,censo)~species,data=wsuv) plot(survfit(Surv(time,censo)~treatment,data=wsuv) plot(survfit...

...etween parcels and among species over time: leaves.cox <- coxph(Surv(time, censo) ~ treatment + species, data= wsuv) When I plot 'survfitt(leaves.cox)', I come up with a survivor curve that starts at 1 ends at 0.4. The problem is that at time 42 almost all leaves are dead. I wander if surfit plot at time 42 should also be close to zero? I followed examples from Venables and Ripley' book. (These analysis are quite new for me). > summary(leaves.cox) Call: coxph(formula = Surv(time, censo) ~ (treatment) + species, data = wsuv) n= 140840 coef exp(coef) se(coef)...