search for: sumc

Displaying 7 results from an estimated 7 matches for "sumc".

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2009 Jan 28
3
for/if loop
...else { hll(pp,1)=ColSums(lselb1(rr:ii,1)) hll(pp,2)=ColSums(lselb2(rr:ii,1)) rr=ii pp=pp+1} } }}} in fact I have the corresponding Gauss code here. But I really don't know how to write such loop in R. rr=1; ii=1; pp=1; do until ii==n+1; if pan[ii,1] ne pp; hll[pp,1]=sumc(lselb1[rr:ii-1,1]); hll[pp,2]=sumc(lselb2[rr:ii-1,1]); rr=ii; pp=pp+1; endif; if ii==n; hll[pp,1]=sumc(lselb1[rr:ii,1]); hll[pp,2]=sumc(lselb2[rr:ii,1]); rr=ii; pp=pp+1; endif; ii=ii+1; endo; -- View this message in context: http://www.nabble.com/for-if-loop-tp21701496p21701496....
2018 Mar 16
3
Discrepancy: R sum() VS C or Fortran sum
...[-5]*p[-5]))/p[5]) u <- a^(1/s)*x^((s-1)/s) dyn.load("sumF.so") u[1] <- u[1]+.0001 ### If we do not add .0001, all differences are 0 s1 <- sum(u) s2 <- .Fortran("sumf", as.double(u), as.integer(n), sf1=double(1), sf2=double(1))[3:4] s3 <- .C("sumc", as.double(u), as.integer(n), sC=double(1))[[3]] s1-s2[[1]] ## R versus compiler sum() (Fortran) [1] -7.105427e-15 s1-s2[[2]] ## R versus manual sum (Fortran [1] -7.105427e-15 s1-s3 ## R Versus manual sum in C [1] -7.105427e-15 s2[[2]]-s2[[1]] ## manual sum versus compiler sum() (Fortr...
2018 Mar 16
1
Discrepancy: R sum() VS C or Fortran sum
...load("sumF.so") >> >> u[1] <- u[1]+.0001 ### If we do not add .0001, all differences are 0 >> s1 <- sum(u) >> s2 <- .Fortran("sumf", as.double(u), as.integer(n), sf1=double(1), >> sf2=double(1))[3:4] >> s3 <- .C("sumc", as.double(u), as.integer(n), sC=double(1))[[3]] >> >> s1-s2[[1]] ## R versus compiler sum() (Fortran) >> >> [1] -7.105427e-15 >> >> s1-s2[[2]] ## R versus manual sum (Fortran >> >> [1] -7.105427e-15 >> >> s1-s3 ## R Versus manual su...
2018 Mar 16
0
Discrepancy: R sum() VS C or Fortran sum
...s)*x^((s-1)/s) > dyn.load("sumF.so") > > u[1] <- u[1]+.0001 ### If we do not add .0001, all differences are 0 > s1 <- sum(u) > s2 <- .Fortran("sumf", as.double(u), as.integer(n), sf1=double(1), > sf2=double(1))[3:4] > s3 <- .C("sumc", as.double(u), as.integer(n), sC=double(1))[[3]] > > s1-s2[[1]] ## R versus compiler sum() (Fortran) > > [1] -7.105427e-15 > > s1-s2[[2]] ## R versus manual sum (Fortran > > [1] -7.105427e-15 > > s1-s3 ## R Versus manual sum in C > > [1] -7.105427e-15 >...
2005 Jun 28
1
faster algorithm for Kendall's tau
Hi, I need to calculate Kendall's tau for large data vectors (length > 100'000). Is somebody aware of a faster algorithm or package function than "cor(, method="kendall")"? There are ties in the data to be considered (Kendall's tau-b). Any suggestions? Regards Ferdinand
2006 Jul 27
6
Any interest in "merge" and "by" implementations specifically for sorted data?
Hi Developers, I am looking for another new project to help me get more up to speed on R and to learn something outside of R internals. One recent R issue I have run into is finding a fast implementations of the equivalent to the following SAS code: /* MDPC is an integer sort key made from two integer columns */ MDPC = (MD * 100000) + PCO; /* sort the dataset by the key */ PROC SORT;
2009 Jan 28
2
t.test in a loop
Hi All, I've been having a little trouble with creating a loop that will run a a series of t.tests for inspection, Below is the code i've tried, and some checks i've looked at. I've used the get(paste()) idea as i was told previously that the use of the eval should try and be avoided. I've run a single syntax to check that my systax is correct and works without any problems