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2012 Jun 04
1
simulation of modified bartlett's test
...(log(A)))-((n1-1)*log(v1)+(n2-1)*log(v2)+(n3-1)*log(v3))
#calculate C
C=1+(1/(3*(k-1))*(((1/(n1-1))+(1/(n2-1))+(1/(n3-1)))-(1/(N-k))))
#calculate layard estimator
xbar1=mean(g1)
xbar2=mean(g2)
xbar3=mean(g3)
sum1=sum((g1-xbar1)^4)
sum2=sum((g2-xbar2)^4)
sum3=sum((g3-xbar3)^4)
sum4=sum((g1-xbar1)^2)
sum5=sum((g2-xbar2)^2)
sum6=sum((g3-xbar3)^2)
y= (N*(sum1+sum2+sum3))/((sum4+sum5+sum6)^2)
#calculate bartlett modified statistic
bar2=B/(C*(1/2)*(y-1))
bar2
pv[i]<-pchisq(bar2,2,lower=FALSE)
}
mean(pv<0.01)
mean(pv<0.05)
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2011 Nov 14
0
[LLVMdev] algebraic (de)optimizations form long chains of dependent operations
Hi,
when I compile (clang -O3) and optimize (opt -O3) C-code like this:
sum1 = val1 + val2;
sum2 = val3 + val4;
sum3 = val5 + val6;
sum4 = val7 + val8;
sum5 = sum1 + sum2;
sum6 = sum3 + sum4;
sum7 = sum5 + sum6;
sum += sum7;
I get bitcode like this:
if.end152: ; preds = %if.then150, %if.else146, %if.end137
%val8.0 = phi i32 [ -2048, %if.then150 ], [ %conv38, %if.else146 ], [ 2047, %if.end137 ]...
2015 Jun 01
2
sum(..., na.rm=FALSE): Summing over NA_real_ values much more expensive than non-NAs for na.rm=FALSE? Hmm...
I'm observing that base::sum(x, na.rm=FALSE) for typeof(x) == "double"
is much more time consuming when there are missing values versus when
there are not. I'm observing this on both Window and Linux, but it's
quite surprising to me. Currently, my main suspect is settings in on
how R was built. The second suspect is my brain. I hope that someone
can clarify the below