Displaying 20 results from an estimated 78 matches for "sum1".
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2007 Sep 01
2
Comparing "transform" to "with"
...them out from
help files or books. So I created a simplified version of what I'm
doing:
rm( list=ls() )
x1<-c(1,3,3)
x2<-c(3,2,1)
x3<-c(2,5,2)
x4<-c(5,6,9)
myDF<-data.frame(x1,x2,x3,x4)
rm(x1,x2,x3,x4)
ls()
myDF
This creates two new variables just fine"
transform(myDF,
sum1=x1+x2,
sum2=x3+x4
)
This next code does not see sum1, so it appears that "transform" cannot
see the variables that it creates. Would I need to transform new
variables in a second pass?
transform(myDF,
sum1=x1+x2,
sum2=x3+x4,
total=sum1+sum2
)
Next I'm trying the same thing...
2004 Jun 29
2
Calculate correctly, but gives an error message
Hi!
I will calculate sum??s in the following way:
E.g.:
a <- rpois(100,20)
b <- rpois(100,5)
x <- data.frame(cbind(a,b))
# the sum??s should be calculated based on a.
attach(x)
sort.nace <- unique(sort(x[,1]))
sum1 <- matrix(ncol=1, nrow=length(sort.nace))
# I calculate the sum of all values of b, which have the same category in a. Eg.:
sum1[1,] <- sum(subset(x, a==sort.nace[1], select=b), na.rm=TRUE)
# or:
sum1[5,] <- sum(subset(x, a==sort.nace[5], select=b), na.rm=TRUE)
# all is ok.
# but when...
2008 Apr 22
4
how to convert non numeric data into numeric?
I am having the following error in my function
function(theta,reqdIRR)
{
theta1<-theta[1]
theta2<-theta[2]
n<-length(reqdIRR)
constant<- n*(theta1+theta2)
sum1<-lapply(reqdIRR*exp(theta1),FUN = sum)
sum2<-lapply(exp(theta2 - reqdIRR*exp(theta1)),FUN = sum)
sum = sum1 + sum2
log.fcn = constant - as.numeric(sum)
result = - log.fcn
return(result)
}
*error : neg.log.gumbel(1,reqdIRR)
Error in sum1 + sum2 : non-numeric argument to binary operator
>...
2016 May 04
2
GVN pass: does global value numbering remove duplicate computations in loops?
...GVN pass. I have
been reading a bit about global value numbering, and from what I
understand, there are polynomial time algorithms for removing duplicate
computations from loops[1].
I have an example program[2] which computes the sum of an array twice, in
two separate accumulators.
Here, sum0 and sum1 are both sums of the array A.
void b01_sums(int size, int* A)
{
int sum0 = 0;
int sum1 = 0;
for (int i = 0; i != size; ++i)
{
sum0 = sum0 + A[i];
sum1 = sum1 + A[i];
printf("sum0: %d\nsum1: %d\n", sum0, sum1);
}
}
I would have expected global value numbering to see...
2008 Oct 17
2
Text (eg. summary) to text file, Howto?
Simple question...
I would like to dump some summries of lm()'s to small seperate text files.
I have looked at:
print(), but it don't support output to file
cat(), but it claims that 'sum1' is a list
write, but that just uses cat()...
The script goes something like this:
...
lmMax <- lm(NUMAMMON ~ YYYY*MM*DD)
sum1 <- summary(lmMax)
# help needed here... how to dump sum1 to a small text file???
...
:-? Martin at Hvidberg.net
2007 Feb 01
3
Help with efficient double sum of max (X_i, Y_i) (X & Y vectors)
...mplement a Cramer-von Mises type test statistic
which involves double sums of max(X_i,Y_j) where X and Y are vectors of
differing length.
I am currently using ifelse pointwise in a vector, but have a nagging
suspicion that there is a more efficient way to do this. Basically, I
require three sums:
sum1: \sum_i\sum_j max(X_i,X_j)
sum2: \sum_i\sum_j max(Y_i,Y_j)
sum3: \sum_i\sum_j max(X_i,Y_j)
Here is my current implementation - any pointers to more efficient
computation greatly appreciated.
nx <- length(x)
ny <- length(y)
sum1 <- 0
sum3 <- 0
for(i in 1:nx) {
sum1...
2018 Jul 10
9
[PATCH 0/7] PowerPC64 performance improvements
The following series adds initial vector support for PowerPC64.
On POWER9, flac --best is about 3.3x faster.
Amitay Isaacs (2):
Add m4 macro to check for C __attribute__ features
Check if compiler supports target attribute on ppc64
Anton Blanchard (5):
configure.ac: Remove SPE detection code
configure.ac: Add VSX enable/disable
configure.ac: Fix FLAC__CPU_PPC on little endian, and add
2014 Sep 29
2
[LLVMdev] Alias Analysis across functions
...Alias" for arrays "A" and "B" in both the functions instead of "NoAlias". What passes should I run in opt before the alias analysis pass to get the accurate result?
Example:
//Note: static and called by func() only.
static int sum(int *A, int *B) {
int i = 0, sum1 = 0;
for (i = 0; i < 100; ++i) {
sum1 += A[i] + B[i];
}
return sum1;
}
int func () {
int A[100], B[100];
int i = 0;
for (; i < 100; ++i) {
A[i] = B[i] = i;
}
return sum(A,B);
}
Arguments to opt: "-mem2reg -basicaa -scev-aa -print-alias-sets"
Output:
Fun...
2010 Sep 24
2
grep contents of file on remote server
Hello,
I am attempting to grep the contents of a key file I have SCP'd to a
remote server. I am able to cat it:
[code]
[bluethundr at LBSD2:~]$:ssh root at sum1 cat /root/id_rsa.pub
root at lcent01.summitnjhome.com's password:
ssh-rsa AAAAB3NzaC1yc2EAAAABIwAAAQEApnUSYyrM96qIBZKjwSNYycgeSv/FAKE-KEY-DATA--KEY-DATA-PWReyVuOn9Fb/uH/FAKE-KEY-DATA-+ttLzUELGrfn/n+FAKE-KEY-DATA-/FAKE-KEY-DATA-/FAKE-KEY-DATA-/FAKE-KEY-DATA-==
bluethundr at lbsd8-2.summitnjhome....
2007 Apr 03
1
Speex ARM4 patch
The attached patch eliminates some warnings while compiling for ARM4
targets. It also simplifies the asm constraints a bit. Now we can use
the ARM4 optimisations when compiling for PortalPlayer targets in Rockbox.
Cheers,
Dan
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2013 Mar 25
2
Faster way of summing values up based on expand.grid
...mycombos[!(mycombos$Var2 == mycombos$Var4),]
mycombos<-mycombos[!(mycombos$Var3 == mycombos$Var4),]
dim(mycombos)
# I want to write sums of elements from values1, values2, and values 3
whose numbers are contained in each column of mycombos. Here is how I am
going it now - using a loop:
mycombos$sum1<-NA
mycombos$sum2<-NA
mycombos$sum3<-NA
for(i in 1:nrow(mycombos)){
mycombos$sum1[i]<-values1[[mycombos[i,"Var1"]]] +
values1[[mycombos[i,"Var2"]]] + values1[[mycombos[i,"Var3"]]] +
values1[[mycombos[i,"Var4"]]]
mycombos$sum2[i]<-values2[[m...
2008 Nov 26
1
SSE2 code won't compile in VC
...);
}
- sum = _mm_add_sd(sum, (__m128d) _mm_movehl_ps((__m128) sum, (__m128)
sum));
+ sum = _mm_add_sd(sum, _mm_unpackhi_pd(sum, sum));
_mm_store_sd(&ret, sum);
return ret;
}
@@ -120,7 +120,7 @@ static inline double
interpolate_product_double(const float *a, const float *b,
sum1 = _mm_mul_pd(f1, sum1);
sum2 = _mm_mul_pd(f2, sum2);
sum = _mm_add_pd(sum1, sum2);
- sum = _mm_add_sd(sum, (__m128d) _mm_movehl_ps((__m128) sum, (__m128)
sum));
+ sum = _mm_add_sd(sum, _mm_unpackhi_pd(sum, sum));
_mm_store_sd(&ret, sum);
return ret;
}
2003 Mar 20
1
rsync 2.5.6 still hangs
...20M (but only about 200K
difference). I tried doing the same with -vvvv (which shows the individual
checksums), and it had this:
recv_generator(file_33,32)
gen mapped file_33 of size 21308244
generating and sending sums for 32
count=10014 rem=580 n=2128 flength=21308244
chunk[0] offset=0 len=2128 sum1=77f93b94
chunk[1] offset=2128 len=2128 sum1=3ec13ce7
chunk[2] offset=4256 len=2128 sum1=99573c59
chunk[3] offset=6384 len=2128 sum1=6a7735a9
<snip>
chunk[7800] offset=16598400 len=2128 sum1=cc0995f1
chunk[7801] offset=16600528 len=2128 sum1=6c2a8f1b
chunk[7802] offset=16602656 len=2128 sum1=5...
2003 Oct 05
2
Possible security hole
...where? I didn't notice
any so here it goes:
sender.c:receive_sums()
s->count = read_int(f);
..
s->sums = (struct sum_buf *)malloc(sizeof(s->sums[0])*s->count);
if (!s->sums) out_of_memory("receive_sums");
for (i=0; i < (int) s->count;i++) {
s->sums[i].sum1 = read_int(f);
read_buf(f,s->sums[i].sum2,csum_length);
..
If I read this right, given high enough s->count makes the malloc()
parameter wraps around to a few bytes while still reading data past it.
Exploiting is probably pretty difficult if at all possible. There would
have to be some...
2002 Apr 23
1
patch: timeout problem solved
.../* tell the other guy how many we are going to be
- doing and how many bytes there are in the last
- chunk */
- write_int(f_out, s->count);
- write_int(f_out, s->n);
- write_int(f_out, s->remainder);
-
- for (i = 0; i < s->count; i++) {
- write_int(f_out, s->sums[i].sum1);
- write_buf(f_out, s->sums[i].sum2, csum_length);
- }
- } else {
- /* we don't have checksums */
- write_int(f_out, 0);
- write_int(f_out, block_size);
- write_int(f_out, 0);
- }
+ /* we don't have checksums */
+ write_int(f_out, 0);
+ write_int(f_out, block_size);
+ write_int(f...
2018 Mar 16
3
Discrepancy: R sum() VS C or Fortran sum
...C
[1] 0
My sumf and sumc are
subroutine sumf(x, n, sx1, sx2)
integer i, n
double precision x(n), sx1, sx2
sx1 = sum(x)
sx2 = 0.0d0
do i=1,n
sx2 = sx2+x(i)
end do
end
void sumc(double *x, int *n, double *sum)
{
int i;
double sum1 = 0.0;
for (i=0; i< *n; i++) {
sum1 += x[i];
}
*sum = sum1;
}
Can that be a bug? Thanks.
--
Pierre Chauss?
Assistant Professor
Department of Economics
University of Waterloo
2016 May 04
2
GVN pass: does global value numbering remove duplicate computations in loops?
...e are polynomial time algorithms for removing
> > duplicate computations from loops[1].
>
> Yes
> The current GVN will not do it.
> > I have an example program[2] which computes the sum of an array
> > twice, in two separate accumulators.
>
> > Here, sum0 and sum1 are both sums of the array A.
>
> > void b01_sums(int size, int* A)
>
> > {
>
> > int sum0 = 0;
>
> > int sum1 = 0;
>
> > for (int i = 0; i != size; ++i)
>
> > {
>
> > sum0 = sum0 + A[i];
>
> > sum1 = sum1 + A[i];
>...
2017 Feb 01
2
RFC: Generic IR reductions
Constant propagation:
%sum = add <N x float> %a, %b
@llvm.reduce(ext <N x double> %sum)
if %a and %b are vector of constants, the %sum also becomes a vector of constants.
At this point you have @llvm.reduce(ext <N x double> %sum) and don't know what kind of reduction do you need.
- Elena
-----Original Message-----
From: Renato Golin [mailto:renato.golin at linaro.org]
2009 Jul 15
0
Fwd: DLLs
...ype
array1= array[1..2,1..num] of Double;
array2=array[1..num,1..num] of longint;
array3=array[1..num,1..num] of Double;
array4=array[1..num] of longint;
pA1=^array1;
pA2=^array2;
pA3=^array3;
pA4=^array4;
pD=^Double;
procedure learning(loc1:pA1;adj1:pA2;alpha:pD); cdecl;
var
i1,i2,neighs:longint;
sum1,sum2:double;
newloc: array [1..2,1..num] of double;
begin
for i1:=1 to 2 do
for i2:=1 to num do
newloc[i1,i2]:=0;
for i1:= 1 to num do
begin
neighs:=0; sum1:=0; sum2:=0;
for i2:= 1 to num do
begin
if (adj1^[i1,i2]=1) then
begin
neighs:=neighs+1;
sum1:=sum1+loc1[1,i2];
sum2:=su...
2018 Mar 16
1
Discrepancy: R sum() VS C or Fortran sum
...n
>> double precision x(n), sx1, sx2
>> sx1 = sum(x)
>> sx2 = 0.0d0
>> do i=1,n
>> sx2 = sx2+x(i)
>> end do
>> end
>>
>> void sumc(double *x, int *n, double *sum)
>> {
>> int i;
>> double sum1 = 0.0;
>> for (i=0; i< *n; i++) {
>> sum1 += x[i];
>> }
>> *sum = sum1;
>> }
>>
>> Can that be a bug? Thanks.
>>
>>
>
--
Pierre Chauss?
Assistant Professor
Department of Economics
University of Waterloo