Displaying 1 result from an estimated 1 matches for "suffolkshannon".
2007 Aug 14
0
Comparing long species lists via Sorensons dissimilarity
...hod = (A + B - 2 * J)/(A + B), terms = c("binary"))
attr(,"method")
I’ve also managed to get diversity indices from R but someone told me that comparing diversity indices is not good because of the way that they are calculated.
>norfolkShannon
3.653768
> suffolkShannon
Suffolk
3.646138
> brecklandShannon
Breckland
4.051742
> otherShannon
Other
3.587403
For the above statistical methods is there a way of laying out the data perhaps via a graph that will show how similar/dissimilar the sites are?
Many thanks for yesterday...