Displaying 2 results from an estimated 2 matches for "subjno".
2005 Feb 21
4
49 histograms on one page
Hi,
I want to do something like this:
par(mfrow=c(7,7))
for (i in 1:49)
hist(RATDACOM[SUBJNO==i],breaks=0.5+(0:6),
main="",xlab="",ylab="",xaxt="n",yaxt="n")
(Don't think about what RATDACOM and SUBJNO are.)
I get an error
Error in plot.new() : Figure margins too large.
36 histograms with mfrow=c(6,6) work.
But the 36 histogr...
2006 May 04
1
Finding ties in data (be)for(e) BradleyTerry
...ith the same frequency. How can I accomplish that using the R-way
(not looping through the entire thing; in reality, I have approx 40
stimuli with around 180 observations of an odd 40 subjects)?
# $lp was left picture; $rp, right one; $wr was the winner/chosen one
by subject.
dat <- data.frame(subjno=gl(4,3),
lp=factor(c(1,3,2,2,3,1,3,1,2,1,2,3), labels=c('a','b','c')),
rp=factor(c(2,1,3,3,1,2,1,2,3,3,1,2), labels=c('a', 'b', 'c')),
wr=factor(c(1,1,2,1,2,2,1,1,2,2,1,2), labels=c('lp', 'rp')))
dat.lp <- subset(dat, wr=='...