Displaying 20 results from an estimated 40 matches for "subid".
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subi
2012 Apr 23
2
plot function creating bars instead of lines
...t data frame
one of those variables (challenge) is a factor with 2 levels. Any
suggestions for getting this to plot as intended would be much appreciated.
Thank you!
************ This is meant to plot a separate line for each subject for each
challenge*************
for (subj in unique(lab.samples$subid)) {
#par(new=T)
plot.new()
par(mfrow=c(2,1))
par(mfg=c(1,1))
plot(data=lab.samples, subset=(subid==subj), cortisol ~ Sample, type='n',
main=paste('Cortisol and Amylase for subject ', as.character(subj)))
for ( t in unique(subset(lab.samples,subid==subj)$challenge) ) {
pa...
2002 Oct 08
2
data.frame merge matching several columns
Greetings,
Is it possible to match several columns in a merge statement? Here is my
problem:
data1 looks like this...
SUBID TARGID ITEM RATING
1 1 1 4
1 1 2 5
1 1 3 3
1 1 4 2
1 1 5 5
......
SUBID is the ID for the raters, TARGID is the ID for the targets being
rated, ITEM ranges from 1 to 64 crossed by TARGID (i.e., all targets...
2012 Mar 19
2
by output into data frame
I could do this in various hacky ways, but what's the right way?
I have a nice application of the by function, which does what I want. The output looks like this:
> auc_stress
lab.samples.stress$subid: 2
cortisol amylase
1 919.05 6834.8
---------------------------------------------------------------------------------------------------------------------------
lab.samples.stress$subid: 3
cortisol amylase
11 728.25 24422.05
etc.
What I want is a data frame roughly like this:
subid c...
2013 Nov 05
0
Sampling question
Hi,
You may try:
dat1 <- structure(list(SubID = 1:8, CSE1 = c(6L, 6L, 5L, 5L, 5L, 5L,
3L, 3L), CSE2 = c(5L, 4L, 5L, 4L, 6L, 4L, 6L, 6L), CSE3 = c(6L,
7L, 5L, 3L, 7L, 3L, 6L, 6L), CSE4 = c(2L, 2L, 5L, 4L, 5L, 6L,
3L, 3L), WSE1 = c(6L, 6L, 5L, 4L, 6L, 4L, 6L, 6L), WSE2 = c(2L,
6L, 5L, 4L, 4L, 3L, 5L, 5L), WSE3 = c(2L, 2L, 4L, 5L, 4L, 7L,
2L...
2010 Nov 18
3
New Sampling question
I have another question about drawing samples from a data frame. This might
sound really tricky. Let me use a data frame I have posted earlier as an
example:
SubID CSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
1 6 5 6 2 6 2 2 4
2 6 4 7 2 6 6 2 3
3 5 5 5 5 5 5 4 5
4 5 4 3...
2011 Jan 18
3
error message
I was running a sampling syntax based on a data frame (ago) of 160 rows and
25 columns. Below are the column names:
> names(ago)
[1] "SubID" "AGR1" "AGR2" "AGR3" "AGR4" "AGR5" "AGR6" "AGR7"
"AGR8"
[10] "AGR9" "AGR10" "WAGR1" "WAGR2" "WAGR3" "WAGR4" "WAGR5" &q...
2013 Apr 30
2
R Function to extract columnNames
Hi,
May be this helps:
funcName<- function(df1, x){
?whatCol=df1[[x]]
?print("Got it")
?print(whatCol)
?}
?
funcName(df,"ColA")
#[1] "Got it"
#[1] 1 2 3 4 5
? funcName(df,"ColB")
#[1] "Got it"
#[1] A B C D E
#Levels: A B C D E
A.K.
>I am trying to extract the 2nd column from a dataframe using a function
called funcName. Note this is an
2010 Apr 30
2
deriving mean from specific cases
Hi all,
I have a large dataset that has >10k entries. The dataset is stored in a
dataframe with the headers:
SubID Condition1 Condition2 Result1 Result2
There are multiple entries for a given SubID(Subject ID). Condition 1 has 3
levels and condition2 has 2 levels (therefore there are 6 possible
combinations all together e.g. Cond1 Level1 x Cond2 Level 1 etc.) and i need
to compute for
1. The mean for a subject...
2007 Aug 01
1
Problem to remove loops in a routine
...in 1:nGRP) { #loop on Group
# l=1
subdata<-subset(ijkdata,ijkdata$GRP==l)
nModel<-nlevels(factor(subdata$MODEL))
#number of models to be plotted in this loop
mylegend<-c("Raw data",levels(factor(subdata$MODEL)))
subID<-nlevels(factor(subdata$ID)) #number of
ID in the new dataset
myplot<-xyplot(Y ~ TIME | ID, #creates plot
data = subdata, type = "l",
groups = MODEL,
observed = subdata$DV,
as.tab...
2008 Oct 02
1
Shadowed Plot
Hello R-users
Kindly assist me with the following plot problem in R-
My data looks like this (shortened because I have about 5000 observations).
dat <- read.table(textConnection("Id Time Y
1 0 194
1 5.22 179
1 5.97 190
2 1.61 265
2 2.1 234
2 16.4 300
2 29.5 345
3 0 212
3 0.36 213
4 0 199
4 1.23 203
5 0 212
5 13.5 216
6 0 222
6 1.6 234" ), header =
2011 Jan 11
1
how to sort new data frame based on the original data frame
I have a really simple question
I have a data frame of 8 variables (the first column is the subjects' id):
SubID G1 G2 G3 G4 W1 W2 W3 W4
1 6 5 6 2 6 2 2 4
2 6 4 7 2 6 6 2 3
3 5 5 5 5 5 5 4 5
4 5...
2010 Nov 15
5
Sampling problem
Hey,
I am hoping someone can help me with a sampling question.
I have a data frame of 8 variables (the first column is the subjects' id):
SubID CSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
1 6 5 6 2 6 2 2 4
2 6 4 7 2 6 6 2 3
3 5 5 5 5 5 5 4 5
4 5 4 3...
2012 Aug 30
0
[PATCH 05/11] vmci_event.patch: VMCI kernel events handling.
...pin_lock_bh(&subscriberLock);
+ event_release(sub);
+ spin_unlock_bh(&subscriberLock);
+
+ return 0;
+}
+
+/*
+ * Find entry. Assumes lock is held.
+ * Increments the VMCISubscription refcount if an entry is found.
+ */
+static struct vmci_subscription *event_find(uint32_t subID)
+{
+ int e;
+
+ for (e = 0; e < VMCI_EVENT_MAX; e++) {
+ struct vmci_subscription *cur;
+ list_for_each_entry(cur, &subscriberArray[e],
+ subscriberListItem) {
+ if (cur->id == subID) {
+...
2012 Aug 30
0
[PATCH 05/11] vmci_event.patch: VMCI kernel events handling.
...pin_lock_bh(&subscriberLock);
+ event_release(sub);
+ spin_unlock_bh(&subscriberLock);
+
+ return 0;
+}
+
+/*
+ * Find entry. Assumes lock is held.
+ * Increments the VMCISubscription refcount if an entry is found.
+ */
+static struct vmci_subscription *event_find(uint32_t subID)
+{
+ int e;
+
+ for (e = 0; e < VMCI_EVENT_MAX; e++) {
+ struct vmci_subscription *cur;
+ list_for_each_entry(cur, &subscriberArray[e],
+ subscriberListItem) {
+ if (cur->id == subID) {
+...
2008 Jun 12
10
Ajax.Updater not working in IE, tried everything
hi,
i am basically using a button, Prototype/AJAX, and PHP to update a
user''s location. something simple as typing ''Chicago, IL''. After the
script, it rewrites the result in a div tag.
here is the form i''m using:
<div id="hometown_result">Aurora, IL</div>
<form action="" method="post"
2010 May 24
5
Means do not tally
Hi all,
here is my situation
In my experiment, I expose 10 subjects to 24 different conditions of
stimuli. Each condition is exposed to the same subject 3x.
This would make each subject have 24x3=72 data points. All the subjects
combined would have 72x10=720 data points with each condition having 30
datapoints.
To find the grand average of each condition, I find the average of all the
2006 Apr 25
6
Searching over multiple MySQL tables
I am racking my brain over this, probably because I only know very
simple mysql functions.
Basically I''ve got a few tables, ex:
Albums (id,name,band_id); Bands (id,name,label_id), and Label (id,name)
I want to search through both album.name, band.name, and label.name
throwing all results into a variable, with no redundant info.
I think what I need to be doing is setting up some
2013 Jan 24
0
Again ACL Postgres dict trouble, no update and raw backtrace
...11:09:59 CET STATEMENT: SELECT dummy,to_user,from_user FROM user_shares
2013-01-24 11:09:59 CET DEBUG: StartTransaction
2013-01-24 11:09:59 CET STATEMENT: SELECT dummy,to_user,from_user FROM user_shares
2013-01-24 11:09:59 CET DEBUG: name: unnamed; blockState: DEFAULT; state: INPROGR, xid/subid/cid: 0/1/0, nestlvl: 1, children:
2013-01-24 11:09:59 CET STATEMENT: SELECT dummy,to_user,from_user FROM user_shares
2013-01-24 11:09:59 CET LOG: statement: SELECT dummy,to_user,from_user FROM user_shares
2013-01-24 11:09:59 CET DEBUG: CommitTransactionCommand
2013-01-24 11:09:59 CET STATEMENT:...
2010 Nov 16
2
Computing Rolling Average
...13 29
Thanks in advance,
Paolo
On 15 November 2010 20:59, wangwallace <talenttree@gmail.com> wrote:
>
> Hey,
>
> I am hoping someone can help me with a sampling question.
>
> I have a data frame of 8 variables (the first column is the subjects' id):
>
> SubID CSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
> 1 6 5 6 2 6 2 2 4
> 2 6 4 7 2 6 6 2 3
> 3 5 5 5 5 5 5 4 5
> 4 5...
2015 Apr 24
0
Férias/Maio/Junho
...20 de Junho de 2015.
Special price from the 30th May until the 20th June 2015. One bedroom apartment without air conditioning and little sea view.
2 pax = 196? (7 noites/nights)
3 pax = 217? (7 noites/nights)
4 pax = 245? (7 noites/nights)
Unsubscribe ( http://ns367630.ip-94-23-27.eu/index.php?subid=2185578&option=com_acymailing&ctrl=user&task=out&mailid=24&key=X03ypWFMVyS91w )
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