Displaying 2 results from an estimated 2 matches for "sub_x".
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sub_n
2009 Jul 03
0
A fast version of ccf () accepting missing values ?
...Y should have same size !")
return
}
if (is.null(lag.before)) {
lag.before <- l_X / 10
#should do 10*log10(N/m)
}
if (is.null(lag.after)) {
lag.after <- l_X / 10
# idem lag.before.
}
res <- list()
res$cor <- rep(0.0, 1 + lag.before + lag.after)
sub_X <- X[ 1 + lag.before : (l_X - lag.after)]
res$delay <- seq(-lag.before, lag.after)
for (i in res$delay) {
sub_Y <- Y[(lag.before+i+1) : (l_X-lag.after+i+1)]
OK <- !(is.na(sub_X) | is.na(sub_Y))
x_select <- sub_X[OK]
y_select <- sub_Y[OK]
res$cor[i+lag.b...
2013 Jan 12
1
Question on broken-line regression: 'segmented' or alternative
...ata$group==3),3]~data[which(data$group==3),2])
abline(reg_3.1, col="green", lty=1)
#Segmented package to estimate breakpoints and determine slopes for
group2 and 3:
subset_data <- subset(data, subset=data$group!=3)
names(subset_data) <- c("sub_group", "sub_x", "sub_y")
attach(subset_data)
X <- model.matrix(~0+sub_group)*sub_x
time.1 <- X[,1]
time.2 <- X[,2]
time.3 <- X[,3]
olm <- lm(sub_y~0 + sub_group + time.1 + time.2)
os <- segmented(olm, seg.Z= ~ time.1 + time.2,
psi=list(time.1=c(14,30)...