Displaying 20 results from an estimated 37 matches for "string1".
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2003 Feb 21
4
Perl question
I'm working on the installer code, but I don't know Perl well enough.
What is a good Perl equivalent of the R statement
if ( s %in% c('string1', 'string2', 'string3') ) ...
I can do it with
if (s == "string1" || s == "string2" || s == "string3") ...
but I've got a feeling there's a better way to do it using associative
arrays.
The real example will have about a dozen fixe...
2004 Dec 02
3
combine two strings
Hello,
I would like to combine two strings while using R.
For instance,
string1 <- "abcde"
string2 <- "WXYZ"
I'd like to combine string1 and string2 into Sting3;
and string3 should be "abcdeWXZY".
Would you please tell me how to do it?
Thank you very much
Ben-Yang
[[alternative HTML version deleted]]
2017 Mar 18
5
AD integration not working after move/version
...moved, only change otherwise is that we had to change to ISO8859-1 for locale, not the argument “LOCALE” that was not longer supported.
# Global parameters
[global]
log file = /var/samba/log/clientlog.%m
dns proxy = No
acl check permissions = False
netbios aliases = string1
server string = string1
name resolve order = hosts bcast
realm = DOMAIN.NET
password server = server3.string1.net sever4.string1.net
# wins server = x.x.x.x
local master = no
workgroup = WGNAME
os level = 0
domain master = no...
2011 Jun 18
3
how to subtract one string from another in R
Dear R Group
Here is what i am trying to do.. but couldnt figure out how..
string<-"ABC DEFG HIJKLM NOPQ RSTUV WXY"
string1<-substr(string,1,4)
I want to create an R object string 2 ( following the logic shown).. R does
not allow string subtraction.. any suggestions how to achieve this?
string2<-string-string1 (it should now hold "DEFG HIJKLM NOPQ RSTUV WXY"
I want to loop this till i reach the end...
2005 Jul 04
1
Colors in mtext
I want to assign different colors to different strings using
mtext(...). However, when I use something like
mtext(text=c("string1","string2","string3"),
col=c("black","blue","red"), side=3, line=0)
string2 and string3 are printed over string1. When I use
paste("string1","string2","string3"), the series of strings are printed
one over each...
2011 May 08
3
%in% operator - NOT IN
Hello everyone,
I am attempting to use the %in% operator with the ! to produce a NOT IN type
of operation. Why does this not work? Suggestions?
> data2[data1$char1 %in% c("string1","string2"),1]<-min(data1$x1)
> data2[data1$char1 ! %in% c("string1","string2"),1]<-max(data1$x1)+1000
Error: unexpected '!' in "data2[data1$char1 !"
Thanks!
Dan
XXXX
[[alternative HTML version deleted]]
2006 Apr 04
1
Indexing a vector by a list of vectors
Hello R-help -
I have
vec <- c("string1", "string2", "string3")
ind <- list(c(1,2),c(1,2,3))
I want "vec" indexed by each vector in the list "ind".
The first element of the list I want would be vec[c(1,2)],
the second element would be vec[c(1,2,3)], like the following.
[[1]]
[1] "str...
2009 Jan 22
4
text vector clustering
Hi,
I am a new user of R using R 2.8.1 in windows 2003. I have a csv file with
single column which contain the 30,000 students names. There were typo
errors while entering this student names. The actual list of names is <
1000. However we dont have that list for keyword search.
I am interested in grouping/cluster these names as those which are
similar letter to letter. Are there any
2003 Feb 23
0
unsubscribe
...e: 4
From: Duncan Murdoch <murdoch@stats.uwo.ca>
To: r-devel@stat.math.ethz.ch
Date: Fri, 21 Feb 2003 14:43:21 -0500
Subject: [Rd] Perl question
I'm working on the installer code, but I don't know Perl well enough.
What is a good Perl equivalent of the R statement
if ( s %in% c('string1', 'string2', 'string3') ) ...
I can do it with
if (s == "string1" || s == "string2" || s == "string3") ...
but I've got a feeling there's a better way to do it using associative
arrays.
The real example will have about a dozen fixed st...
2017 Mar 18
0
AD integration not working after move/version
...step forward to a supported Samba version. :-)
https://wiki.samba.org/index.php/Samba_Release_Planning
> # Global parameters
> [global]
> log file = /var/samba/log/clientlog.%m
> dns proxy = No
> acl check permissions = False
> netbios aliases = string1
> server string = string1
> name resolve order = hosts bcast
> realm = DOMAIN.NET
> password server = server3.string1.net sever4.string1.net
> # wins server = x.x.x.x
> local master = no
> workgroup = WGNAME
> os...
2010 Mar 27
1
string width calculation
...ONT)
mtext("Y", cex=2, adj=??, family=DIFFERENTFONT)
My question regards how to calculate "adj" for the second string.
I tried the following (different strings here and the same font was used for both strings - even under these circumstances, it does not work correctly):
> STRING1 <- "0123456789 0"
> STRING2 <- " x "
> pdf("GREEK.pdf", width=10, height=8)
> par(mfrow=c(1,1))
> WIDTH1 <- strwidth("0123456789", cex=1, units="inches", family="", font=1)
> WIDTH2 <- strwidth("0&...
2003 Apr 28
1
Red Hat 9 regex symbol conflict
...ation in REGS (if REGS and BUFFER->no_sub are nonzero). */
! extern int re_search
_RE_ARGS ((struct re_pattern_buffer *buffer, const char *string,
int length, int start, int range, struct re_registers *regs));
/* Like `re_search', but search in the concatenation of STRING1 and
STRING2. Also, stop searching at index START + STOP. */
! extern int re_search_2
_RE_ARGS ((struct re_pattern_buffer *buffer, const char *string1,
int length1, const char *string2, int length2,
int start, int range, struct re_registers *regs, int stop));...
2017 Mar 18
0
AD integration not working after move/version
...status of the integration in any
> way?
You will probably need to join the new domain member again.
> # Global parameters
> [global]
> log file = /var/samba/log/clientlog.%m
> dns proxy = No
> acl check permissions = False
> netbios aliases = string1
> server string = string1
> name resolve order = hosts bcast
> realm = DOMAIN.NET
> password server = server3.string1.net sever4.string1.net
> # wins server = x.x.x.x
> local master = no
> workgroup = WGNAME
> os...
2009 Jan 10
0
RMySQL CREATE TABLE error
...HERE participant = '005_avg' AND roi = '1033' AND
nogestureFDR > 1.95;")
9 > dbSendQuery(con, temp1)
<MySQLResult:(436,20,1)>
10 > dbSendQuery(con, temp2)
<MySQLResult:(436,20,2)>
11 > dbSendQuery(con, temp3)
<MySQLResult:(436,20,3)>
12 > query.string1 <- paste("SELECT t.timeseries_id, t.timeseries_signal
FROM MyTemporaryTable1 t, MyTemporaryTable3 v WHERE t.participant =
v.participant AND t.roi = v.roi AND t.voxel_id = v.voxel_id;",sep="")
13 > query.string2 <- paste("SELECT t.timeseries_id, t.timeseries_signa...
2017 Mar 18
2
AD integration not working after move/version
...n domain: failed to connect to AD: Server not found in Kerberos database
>
>
>> # Global parameters
>> [global]
>> log file = /var/samba/log/clientlog.%m
>> dns proxy = No
>> acl check permissions = False
>> netbios aliases = string1
>> server string = string1
>> name resolve order = hosts bcast
>> realm = DOMAIN.NET
>> password server = server3.string1.net sever4.string1.net
>> # wins server = x.x.x.x
>> local master = no
>> workgroup = W...
2007 Aug 26
2
Character position command
This is a very simple question, so I apologize I couldn't find it online:
I want to shorten the string 'apples.pears' to 'apples'.
string='apples.pears'
string1=substr(string,0,x)
For x above, I would like to have a command like charAt(string,"."), i.e.
the position of the period in the word, but I can't seem to find a charAt
command in R.
Thank you.
[[alternative HTML version deleted]]
2006 Jun 19
2
fuzzy search
...at are people doing to find records
based on fuzzy string matches? For example, if you wanted to find a
Person with name "David Heinemeier Hansson" but searched using the
string "Dave Hansson".
Currently I am find_by_sql that calls the PostgreSQL function
"levenshtein(string1, string2)" which returns results with a score
indicating how close the matches are. It is OK, but nowhere good as I
would hope. Any better suggestions?
thanks,
Jeff
--
Posted via http://www.ruby-forum.com/.
2012 Apr 19
1
Compare String Similarity
Dear All,
I need to estimate the level of similarity of two strings. For example:
string1 <- c("depending","audience","research", "school");
string2 <- c("audience","push","drama","button","depending");
The words in string may occur in different order though. What function would you recommen...
2012 May 08
1
Extracting Hash-tagged word from Tweets
...ort @hollandtrade @dutchembassyUK" (Tweet download)
I want a code that will extract this:
#Dutch companies #london2012, #olympics, #sport
I have used the under-listed code in Stringr which return these outputs I did not require:
> str_extract_all("#<-a-z, #<-A-Z", "[[string1:string10]]") [[1]]
character(0)
> str_extract_all("#<-a-z, #<-A-Z", "[[string9]]") [[1]]
character(0)
> str_extract_all("#=[1:10]", "#+a-z") [[1]]
character(0)
str_extract_all("#=[1:10]", "#+") [[1]]
[1] "#"...
2013 Nov 21
1
[LLVMdev] Problem with labels
......)* @scanf(i8* %format, i32* %ptr)
ret void
}
define void @writeInteger(i32 %integer) {
%format = getelementptr [3 x i8]* @.intFormat, i32 0, i32 0
call i32 (i8*, ...)* @printf(i8* %format, i32 %integer)
ret void
}
@b = private global i32 0
@c = private global i32 0
@a = private global i32 0
@.string1 = internal unnamed_addr constant [8 x i8] c"valeur:\00"
define void @find() {
%tmp1 = load i32* @c
store i32 %tmp1, i32* @b
Until2:
%a6 = load i32* @a
%b7 = load i32* @b
%conditionVar5 = icmp slt i32 %a6, %b7
br i1 %conditionVar5, label %EndUntil4, label %Call3
Call3:
call void @diff()
b...