Displaying 3 results from an estimated 3 matches for "stress3".
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stress
2011 Mar 17
2
Incorrect degrees of freedom in SEM model using lavaan
...myCov = matrix(c(24.40, 0, 0, 0, 0, 0, 0, .03, .03, 0, 0, 0, 0, 0, 6.75, -
.08, 519.38, 0, 0, 0, 0, .36, .01, 2.74, .18, 0, 0, 0, .51, .0, -.31, .02,
.2, .0, 0, -.17, .0, -1.6, -.04, .01, .25, 0, -.1, .02, -.03, .0, -.01, .01
, .02), nrow=7, byrow=TRUE, dimnames=list(c("Internet", "Stress3",
"HHincome", "Race", "Age", "Gender", "Stress1"), c("Internet", "Stress3",
"HHincome", "Race", "Age", "Gender", "Stress1")))
model = '
Internet ~ HHincome + Race + Ag...
2012 Sep 08
0
reshape and geeglm problem
...E" "Neuro" "Intervention.x" "depr0" "error1_1.x" "error1_2.x"
[15] "error1_3.x" "error1_4.x" "stress0" "stress1" "stress2" "stress3" "stress4"
[22] "hours1" "hours2" "hours3" "hours4" "subject"
First I reshape my data to prepare for geeglm:
compl$subject <- factor(rownames(compl))
nobs <- nrow(compl)
c...
2003 Apr 20
1
survreg penalized likelihood?
...e dead
1 1 50 FALSE
2 1 50 FALSE
3 1 50 FALSE
# All three observations at Stress=1 are censored.
> Fit <- survreg(Surv(Time, dead)~Stress-1, data=Data)
> Fit
Call:
survreg(formula = Surv(Time, dead) ~ Stress - 1, data = Data)
Coefficients:
Stress1 Stress2 Stress3
41.3724178 2.2819204 -0.5281005
Scale= 0.2577886
Loglik(model)= -6.6 Loglik(intercept only)= -22.1
Chisq= 30.88 on 2 degrees of freedom, p= 2e-07
n= 9
# Even though 100% of observations at Stress=1 are censored,
# I still get a finite estimate for log(characteristics life).
Thanks,
Spencer G...