Displaying 20 results from an estimated 129 matches for "strats".
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2024 May 15
2
Extracting values from Surv function in survival package
OS X
R 4.3.3
Colleagues
I have created objects using the Surv function in the survival package:
> FIT.1
Call: survfit(formula = FORMULA1)
n events median 0.95LCL 0.95UCL
SUBDATA$ARM=1, SUBDATA[, EXP.STRAT]=0 18 13 345 156 NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=1 13 5 NA 186 NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=2 5
2015 Jun 15
2
Different behavior of model.matrix between R 3.2 and R3.1.1
Terry - your example didn't demonstrate the problem because the variable
that interacted with strata (zed) was not a factor variable.
But I had stated the problem incorrectly. It's not that there are too
many strata terms; there are too many non-strata terms when the variable
interacting with the stratification factor is a factor variable. Here
is a simple example, where I have
2015 Jun 15
2
Different behavior of model.matrix between R 3.2 and R3.1.1
Terry - your example didn't demonstrate the problem because the variable
that interacted with strata (zed) was not a factor variable.
But I had stated the problem incorrectly. It's not that there are too
many strata terms; there are too many non-strata terms when the variable
interacting with the stratification factor is a factor variable. Here
is a simple example, where I have
2024 May 16
1
Extracting values from Surv function in survival package
Hi Dennis,
look at the help page for summary.survfit, the Value n.event.
G?ran
On 2024-05-15 22:41, Dennis Fisher wrote:
> OS X
> R 4.3.3
>
> Colleagues
>
> I have created objects using the Surv function in the survival package:
>> FIT.1
> Call: survfit(formula = FORMULA1)
>
> n events median 0.95LCL 0.95UCL
>
2017 Oct 19
2
Select part of character row name in a data frame
Dear R contributors,
I have a problem in selecting in an efficient way, rows of a data frame according to a condition,
which is a part of a row name of the table.
The data frame is made of 64 rows and 2 columns, but the row names are very long but I need to select them according to a small part of it and perform calculations on the subsets.
This is the example:
X Y
"Unique to
2015 Jun 16
1
Different behavior of model.matrix between R 3.2 and R3.1.1
Terry Therneau has been very helpful on r-help but we can't figure out
what change in R in the past months made extra columns appear in
model.matrix when the terms object is subsetted to remove stratification
factors in a Cox model. Terry has changed his logic in the survival
package to avoid this issue but he requires generating a larger design
matrix then dropping columns.
A simple
2017 Oct 19
2
Select part of character row name in a data frame
Thanks a lot, so simple so efficient!
I will study more the grep command I did not know.
Thanks!
Francesca Pancotto
> Il giorno 19 ott 2017, alle ore 12:12, Enrico Schumann <es at enricoschumann.net> ha scritto:
>
> df[grep("strat", row.names(df)), ]
[[alternative HTML version deleted]]
2009 Oct 01
5
How to use Subpopulation data?
Dear Helpers
I have a sample frame and i have sampled from it using three methods and now i want to calculate the statistics but i only get the population parameters.
H <- matrix(rnorm(100, mean=50000, sd=5000))
sampleframe=data.frame(type=c(rep("H",100)),value=c(H))
sampleframe
str=strata(sampleframe,c("type"),size=c(20,), method="srswor")
2017 Oct 19
0
Select part of character row name in a data frame
(Re-)read the discussion of indexing (both `[` and `[[`) and be sure to get clear on the difference between matrices and data frames in the Introduction to R document that comes with R. There are many ways to create numeric vectors, character vectors, and logical vectors that can then be used as indexes, including the straightforward way:
df[ c(
"Unique to strat ",
"Unique
2010 Apr 29
2
Rotating Titles
Hi All,
I am looking for help in rotating species titles produced using the
strat.plot( ) function in the rioja package. This function produces a
stratigraphic plot of paleoenvironmental data. Currently the titles of each
species are plotted vertically while they are typically plotted at a 45
degree angle in other programs. Does anyone have any idea of how to rotates
these titles?
Below is an
2011 Mar 10
2
using lapply
I have a function with the follow signare:
apply.strategy(instr, strat)
where instr and strat are both objects of classes instrument and strategy
respectively.
I want to apply this function to a list that holds objects of the class
instrument.
Currently I am doing this by explicit looping:
for(i in length(instr.list) ) {
apply.strategy(instr.list[[i]], my.strat)
}
Is it possible to
2017 Oct 19
0
Select part of character row name in a data frame
Quoting Francesca PANCOTTO <f.pancotto at unimore.it>:
> Dear R contributors,
>
> I have a problem in selecting in an efficient way, rows of a data
> frame according to a condition,
> which is a part of a row name of the table.
>
> The data frame is made of 64 rows and 2 columns, but the row names
> are very long but I need to select them according to a small
2011 Aug 19
1
adding text to a plot created with strat.plot() from package rioja
I have a plot created with strat.plot() from package rioja. When
the plot is created with scale.percent=FALSE, each x axes is labeled at
0 and its maximum. However, when scale.percent=TRUE, the x axes are not
labeled. I need to use scale.percent=TRUE and I need labels for the x axes.
I have been able to add labels to the x axes with mtext but it is
very tedious to find the correct
2008 Jun 17
3
Capturing coxph warnings and errors
Hi,
I have a script that takes a subset of genes on a microarray and tries
to fit a coxph model to the expression values for each gene. This seems
to work fine but in some cases it produces warnings and/or errors.
For example:
Error in fitter(X, Y, strats, offset, init, control, weights = weights, :
NA/NaN/Inf in foreign function call (arg 6)
In addition: Warning message:
In fitter(X, Y, strats, offset, init, control, weights = weights, :
Ran out of iterations and did not converge
In this situation I would like to:
1) Deal with it so that it...
2005 Oct 12
1
Problem with a barplot...
Hello,
I'm having a bit of a problem with a plot, and I'm hoping that someone might
be able to help. I'm running the R Cocoa Gui v1.12 on OS X 10.4.2, and I'm
doing a stacked bar plot. The plot itself is quite simple:
barplot(as.matrix(s.strats.in),main="Strategy when strong", col=strat.col)
where s.strats.in is a matrix with a number of rows that define the height
of each stacked bar. However, ever since I expanded the number of columns
from 100 to 500, the borders of the bars are overwhelming the plot (the bars
are proportio...
2007 Mar 27
0
Error when calling residual.plots() on an ANOVA object
Dear *,
I have to perform an ANOVA analysis to study the effects on the
performance of some algorithmic components in the design of my
algorithm.
I have done a full factorial design for the following 5 factors (my
response variable is "best"):
$ model :'data.frame': 3360 obs. of 6 variables:
..$ best : num [1:3360] 0.108 0.573 0.625 1.057 0.451 ...
2004 Sep 09
2
Rd syntax error detected in CRAN daily checks
Please forgive me if you already received this. I had an e-mail sending
glitch this morning.
http://cran.r-project.org/src/contrib/checkSummary.html reported an
error in Design.trans.Rd
* checking Rd files ... ERROR
Rd files with syntax errors:
/var/mnt/hda3/R.check/r-devel/PKGS/Design/man/Design.trans.Rd:
unterminated section 'alias'
The .Rd file is attached. It begins
2007 May 04
3
Error in if (!length(fname) || !any(fname == zname)) { :
Dear R users,
I tried to fit a cox proportional hazard model to get estimation of stratified survival probability. my R code is as follows:
cph(Surv(time.sur, status.sur)~ strat(colon[,13])+colon[,18] +colon[,20]+colon[,9], surv=TRUE)
Error in if (!length(fname) || !any(fname == zname)) { :
missing value where TRUE/FALSE needed
Here colon[,13] is the one that I want to stratify and the
2006 Nov 20
1
Proportional data with categorical explanatory variables
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2007 Feb 05
1
ran out of iteration in coxph
hi,
I applied coxph to my matrix of 300 samples and 215 variables and got the following error
Error in fitter(X, Y, strats, offset, init, control, weights = weights, :
NA/NaN/Inf in foreign function call (arg 6)
In addition: Warning message:
Ran out of iterations and did not converge in: fitter(X, Y, strats, offset, init, control, weights = weights,
26% of time data is censored and here is the result of densi...