search for: str_split

.... That is all. Can this code improved ? data <- read.table("D:\\Log Analysis\\26-9-2013\\concurrentusage-node1",sep="",header=T,stringsAsFactors=FALSE, fill=TRUE) var <- c("Foreign.Address") data[,var] <- sapply(data[,var],function(x) ifelse(length(unlist(str_split(x,":")))==5,unlist(str_split(x,":"))[4],unlist(str_split(x,":"))[1])) var <- c("Local.Address") data[,var] <- sapply(data[,var],function(x) ifelse(length(unlist(str_split(x,":")))==5,paste(unlist(str_split(x,":"))[4],":",u...

...#39;C:/Users/bdominguez/Documents/H0711/Bond/1909/'? archivos<-list.files(path=ruta,pattern = '*.pdf')? ? ? imagen <- image_read_pdf(path=paste(ruta,"/",nombre,".pdf",sep=""))? prueba <-image_ocr(imagen, language = 'eng')? lineas<-unlist(str_split(prueba,pattern = "\n"))? lineasp<-unlist(str_split(prueba[2],pattern = "\r\n"))? ? newnom <- NULL? renglones <- NULL? for (nombre in archivos){? subgrupo <- str_extract(str_extract(nombre,pattern = subgrupo_rg),pattern = "[0-9]{1,3}")? imagen <- imag...

...rg> Asunto: Re: [R-es] Consulta Hola, Estos mensajes de error no son por el paquete pdftools. Las funciones image_read_pdf e image_ocr son del paquete magick. ¿Lo tienes instalado? ¿Lo tienes cargado? Según el script sí, pero asegúrate de que library(magick) no da ningún error. La otra función ?str_split? es del paquete stringr, pasa lo mismo: tiene que estar cargado para poder utilizar sus funciones. Saludos, Emilio El 24 sept 2019, a las 16:20, BERENICE DOMINGUEZ SANCHEZ <ds_bere en hotmail.com<mailto:ds_bere en hotmail.com>> escribió: Emilio Buen día, si me manda un error muy esp...

...ual information in algorithm ##### CULTURES ##### for (i in names(AB_list)) { ab_data <- dataset_ab[dataset_ab$middel == i,] #get info for this AB from dataset_ab # Extract and split the diagnoses, dosering, and duur info for the current antibiotic ab_diagnoses <- str_split(ab_data$diagnoses, pattern = " \\| ")[[1]] ab_diagnose_dosering <- str_split(ab_data$`diagnose dosering`, pattern = " \\| ")[[1]] ab_diagnose_duur <- str_split(ab_data$`diagnose duur`, pattern = " \\| ")[[1]] # Find the index of the current diagn...

Dear R forum I have a data.frame df = data.frame(currency_type = c("EURO_o_n", "EURO_o_n", "EURO_1w", "EURO_1w", "USD_o_n", "USD_o_n", "USD_1w", "USD_1w"), rates = c(0.47, 0.475, 0.461, 0.464, 1.21, 1.19, 1.41, 1.43))   currency_type     rates 1      EURO_o_n   0.470 2      EURO_o_n   0.475 3       EURO_1w   0.461

...Here is a solution to the dates without leading zeros: pou1 <- function(x) { #Note: x is a data frame #Assume that Column 1 has the date #Column 2 has station #Column 3 has min #Column 4 has max library(stringr) w <- character(length=nrow(x)) z <- str_split(x[,1],"/") for(i in 1:nrow(x)) { u <- str_pad(z[[i]][1:3],width=2,pad="0") w[i] <- paste(u,sep="",collapse="/") } a <- as.Date(w,"%m/%d/%Y") This is not particularly elegant, but it does the trick. Thanks, E...

Hello! I have a column in my data frame that I have to split: I have to distill the numbers from the text. Below is my example and my solution. x<-data.frame(x=c("aaa1_bbb1_ccc3","aaa2_bbb3_ccc2","aaa3_bbb2_ccc1")) x library(stringr) out<-as.data.frame(str_split_fixed(x$x,"aaa",2)) out2<-as.data.frame(str_split_fixed(out$V2,"_bbb",2)) out3<-as.data.frame(str_split_fixed(out2$V2,"_ccc",2)) result<-cbind(x,out2[1],out3) result My problem is: str_split.fixed is relatively slow. In my real data frame I have over 80,000 ro...

...ace": > > bg3_race_sum$label |> > (\(.) sub('^ !!', '', .))() |> > (\(.) gsub('[^!]*!!', ' ', .))() > > But that solution could have been impossible if the task was slightly > different. > >> I can split the label using str_split(label, pattern = "!!") to get a >> vector of strings, but don't know how to work on the last string and >> all the rest of the strings separately. > > str_split() would have given you a list of character vectors. You can > use lapply to evaluate a function on eac...

You can use na.strings="" in read.table() or read.csv() library(stringr) vec1<-unlist(str_split(readLines(textConnection("3,7,11,,12,14,15,,17,18,19")),",")) ?vec1[vec1==""]<- NA ?vec1 # [1] "3"? "7"? "11" NA?? "12" "14" "15" NA?? "17" "18" "19" #or scan(text="3,7,1...

Hi, May be this helps: vec<- "this is a nice text with nice characters" library(stringr) ?vec2<-unlist(str_match_all(vec,"\\w+")) #or # vec2<-str_split(vec," ")[[1]] res<-unique(lapply(vec2,function(x) which(!is.na(match(vec2,x))))) ?names(res)<- unique(vec2) res #$this #[1] 1 # #$is #[1] 2 # #$a #[1] 3 # #$nice #[1] 4 7 # #$text #[1] 5 # #$with #[1] 6 # #$characters #[1] 8 A.K. >Hi, >I have tried some different packages i...

...os.words, neg.words) { # clean up sentences with R?s regex-driven global substitute, gsub(): sentence = gsub(?[[:punct:]]?, ?, sentence) sentence = gsub(?[[:cntrl:]]?, ?, sentence) sentence = gsub(?\\d+?, ?, sentence) # and convert to lower case: sentence = tolower(sentence) # split into words. str_split is in the stringr package word.list = str_split(sentence, ?\\s+?) # sometimes a list() is one level of hierarchy too much words = unlist(word.list) # compare our words to the dictionaries of positive & negative terms pos.matches = match(words, pos.words) neg.matches = match(words, neg.words)...

Hola, Vaya desastre al mandar la cabecera de la base de datos. Al enviarlo, se veía bien, pero está visto que por el camino la cosa se torció. Siguiendo el consejo de Javier, he subido un pequeño fragmento al DropBox. He quitado algunas especies para no hacerlo muy largo. Espero que ésta vez no haya problemas. https://www.dropbox.com/s/q7zla50oq7owg8k/CPUE.csv?dl=0 Un saludo y gracias Juan

...iones, es la stringr si tienes los datos más o menos adecuadamente dispuestos. > Puede que en tu caso funciones como la de str_extract(string, pattern) sea interesante para localizar exactamente el sitio donde está el espacio en blanco o para extraer en 2 componentes los 2 elementos puede usarse str_split(string, pattern, n = Inf) > Espero haber ayudado > Un saludo, Francisco > > Date: Mon, 12 Jan 2015 20:09:06 -0300 > > From: javier.ruben.marcuzzi en gmail.com > > To: r-help-es en r-project.org > > Subject: Re: [R-es] Abreviar nombres ciéntificos > > > >...

Numbers -- thanks. Another clever trick. On 5/25/2018 11:54 AM, Greg Minshall wrote: > Evan, > > are you really looking at numbers, or just at character strings (that, > in your case, happen to be numbers)? if just characters, this rather > odd combination of strsplit() and Reduce() might do the trick: > ---- >> x <- '10110111' >> print(x) > [1]

Hi Group, I have a question on Stringr package I have a table like this X Y ab su - di ac pi - tu ad tu - tu I want output like this X Y ab su ab di ac pi ac tu ad tu ad tu I am wondering if this operation can be done using stringr package (only) ? [[alternative HTML version deleted]]

Dear all, I would like to ask you if R has a library that can work with different GPS formats For example  I have a string of this format N50° 47.513 E006° 03.985 and I would like to convert to GPS decimal format. that means for example converting the part N50° 47.513 to 50 + 47/60 + 513/3600. Is it possible to do that with R? What is the name of such a library? I would like to thank you in

...tidyr) > > data_help <- read_csv("data_help.csv") > cat_help <- read_csv("cat_help.csv") > > # Helper function to split the Items and create a data_frame > split_items <- function(items){ > x <- items$Items_purchased_on_Receipts %>% > str_split(pattern = ",") %>% > unlist(use.names = FALSE) > > data_frame(Item = x, Purchase_ID = items$Purchase_ID) > } > > data_help <- > data_help %>% > mutate(Purchase_ID = 1:n()) %>% > group_by(Purchase_ID) %>% > do(split_items(.)) &gt...

...brary(dplyr) library(stringr) library(tidyr) data_help <- read_csv("data_help.csv") cat_help <- read_csv("cat_help.csv") # Helper function to split the Items and create a data_frame split_items <- function(items){ x <- items$Items_purchased_on_Receipts %>% str_split(pattern = ",") %>% unlist(use.names = FALSE) data_frame(Item = x, Purchase_ID = items$Purchase_ID) } data_help <- data_help %>% mutate(Purchase_ID = 1:n()) %>% group_by(Purchase_ID) %>% do(split_items(.)) cat_help %>% gather("Foo", "Item...

Hello, I have a question and need your help urgently. I am new to R but want to learn it. I have several files in a folder which I have imported to R using : temp = list.files(pattern="*.txt") >myfiles = lapply(temp, read.delim) The resulting files are on the workspace stored as List[110]. So they are 110 files in the list. Each file has several different columns and rows. My

Hola a tod en s, Estoy tratando de abreviar nombres ciéntificos pero no me gusta cómo queda usando make.cepnames de la librería vegan. Me gustaría poderlos abreviar así, Hymenocephalus italicus --> H.italicus Merluccius merluccius --> M.merluccius He probado con varias opciones y no consigo dar con ello. Estoy casi seguro de que es algo relativamente sencillo, pero no doy con ello.