Displaying 6 results from an estimated 6 matches for "steenking".
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steenkin
2002 Sep 13
1
[LLVMdev] Linux-x86 Compatability
ISSUE: Linux doesn't have any steenking SIGEMT signal, as referred to in
lib/Support/Signals.cpp.
ACTION: Wrap the use with a #ifdef SIGEMT / #endif.
PATCH: Apply from llvm top-level directory with "patch -p0".
--
Casey Carter
Casey at Carter.net
ccarter at uiuc.edu
AIM: cartec69
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An...
2011 May 06
1
(no subject)
I'm using the survey api. I am taking 1000 samples of size of 100 and
replacing 20 of those values with missing values. Im trying to use
sequential hot deck imputation, and thus I am trying to figure out how
to replace missing values with the value before it. Other things I have
to keep in mind is if there are two missing values side by side, how do I
replace both those values with the
2010 Apr 19
2
Kaplan-Meier survfit problem
When I try to the code from library(survival) of library(ISwR),
the following code
survfit(Surv(days,status==1))
that could produce Kaplan-Meier estimates shows the following error
"Error in survfit(Surv(days, status == 1)) :
Survfit requires a formula or a coxph fit as the first argument"
How it can be done in R.2.10
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2001 Sep 20
2
win32:DEVICE_Open Unknown VxD A:. Try --winver nt40 or win31 !
Hi,
I was hoping to use wine to run one of those stupid windows binaries that
generate a floppy (at least IBM has a clue, and also offers the raw floppy
image for dd-ing)
In this case, the culprit is seagate's seatools:
http://www.seagate.com/support/seatools/
I installed wine under debian unstable (Version: 0.0.20010824-1) and when I
run the windows binary under wine, it runs but
2011 Jan 10
2
How to save the output of "split" command as series of .csv files
Hello,
I am looking for a way to quickly split a data frame containing daily
temperature readings into a series of individual data frames, one for each
year, in order to save them as individual .csv files which will be named
according to Year. I would prefer not to use a series of "subset" commands
given that there are a differing number of years for the various location.
The data
2010 Dec 07
4
Creating binary variable depending on strings of two dataframes
Hi,
consider the following two dataframes:
x1=c("232","3454","3455","342","13")
x2=c("1","1","1","0","0")
data1=data.frame(x1,x2)
y1=c("232","232","3454","3454","3455","342","13","13","13","13")