search for: stdeviations

..., as the number of observations increases variance will fall. In particular, for 30,000 observations, the StDev is calculated as follows: SQRT(0.2/365)/SQRT(30000) = 0.0001351474 = {1 STDEV} The average of the values in the table above, 0.23, is [(0.23/365) - (0.14/365)]/0.0001351474 = 1.824 StDeviations above the mean. As you can see Most of the 20 sets had realized values about 2-3 StDeviations higher than the mean. Something is wrong. Thank you for considering this bug report.

I'm creating my own package for personal and I'm having trouble getting it to a point where R (v 2.3.1) will recognise it. I've followed two different tutorials for how to create the package structure and the DESCRIPTION file ( http://web.maths.unsw.edu.au/~wand/webcpdg/rpack.html , http://www.maths.bris.ac.uk/~maman/computerstuff/Rhelp/Rpackages.html#Lin-Lin ). I'm still getting