search for: stda

...se that takes values from 0 thru 10, and a factor that has 5 levels (unordered) ... I have a mean and std dev for each of the 5 levels and need to obtain a p-value indicating whether there is evidence of a difference between these means. Mean Std Dev N Level A mA stdA nA Level B mB stdB nB Level C mC stdC nC Level D mD stdD nD Level E mE stdE nE My current plan is to assume normally distributed responses and use the known mean and std dev to generate data points which can be combi...

...ble information is all that you need in order to do the usual ANOVA. Most elementary statistics texts will tell you how. The ``standard 1-way ANOVA'' assumes that the population standard deviations are equal for the various levels. You thus form SSE by ``pooling'': SSE = (nA-1)*stdA^2 + ... + (nE-1)*stdE^2 You form the sum of squares for the factor as SSF = nA*(mA-mBar)^2 + ... + nE*(mE-mBar)^2 where ``mBar'' is the `grand mean'': mBar = (nA*mA + ... + nE*mE)/n where in turn n = nA + ... + nE Then form MSF = SSF/4 and MSE = SSE/(n - 5) (4 because 4 =...