Displaying 20 results from an estimated 236 matches for "stationari".
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stationary
2008 Jun 26
1
stationary "terminology" time series question
...terms of its acf. so,
i'm confused in terms of what ithe statistical definition of stationary
is
as box jenkins define it ?
I don't have their text in front of me but I don't remember them having
an example such as below when they talk about needing to difference
series
to achieve stationarity. thanks for any insights or a text that talks
about this.
x <- seq(pi,-pi,by=-pi/4)
y <- sin(x)
plot(x,y)
acf(y)
P.S: this question arose because a colleague asked me to look at the
plot of his series and the associated acf and he claims it's a
stationary series and
I'm trying...
2007 Dec 08
2
time series tests
...melbmax)
Box-Pierce test
data: melbmax
X-squared = 1893.093, df = 1, p-value < 2.2e-16
> Box.test(melbmax,type="Ljung-Box")
Box-Ljung test
data: melbmax
X-squared = 1894.650, df = 1, p-value < 2.2e-16
> kpss.test(melbmax)
KPSS Test for Level Stationarity
data: melbmax
KPSS Level = 0.1163, Truncation lag parameter = 13, p-value = 0.1
Warning message:
p-value greater than printed p-value in: kpss.test(melbmax)
> x=time(melbmax)
> y=as.vector(melbmax)
> melbmaxsaz=lowess(x,y,f=0.05)$y
> melbmaxtrend=lowess(x,y,f=0.5)$y
> melbma...
2007 Nov 26
3
Time Series Issues, Stationarity ..
Hello,
I am very new to R and Time Series. I need some help including R codes
about the following issues. I' ll really appreciate any number of
answers...
# I have a time series data composed of 24 values:
myinput = c(n1,n2...,n24);
# In order to make a forecasting a, I use the following codes
result1 = arima(ts(myinput),order = c(p,d,q),seasonal = list(order=c(P,D,Q)))
result2 =
2013 Jun 23
1
Scaling Statistical
Short question: Is it possible to use statistical tests, like the Augmented
Dickey-Fuller test, in functions with for-loops? If not, are there any
alternative ways to scale measures?
Detailed explanation: I am working with time-series, and I want to flag
curves that are not stationary and which display pulses, trends, or level
shifts.
>df
DATE ID VALUE2012-03-06 1
2007 Aug 16
2
ADF test
...0 5.20 5.20 5.21 5.21 5.21 5.21 5.21 5.21 5.22 5.22 5.23
[127] 5.23 5.23 5.23 5.24 5.24 5.24 5.25 5.24 5.24 5.25 5.26 5.26 5.26 5.26 5.26 5.26 5.26 5.27
[145] 5.27 5.26 5.27 5.27 5.28 5.29 5.29 5.29 5.29 5.30 5.30 5.30 5.31 5.31 5.31 5.32 5.32 5.33
[163] 5.33
Now I want to conduct a test for stationarity using ADF test :
> adf.test((data[,1]), "stationary", 0)
Augmented Dickey-Fuller Test
data: (data[, 1])
Dickey-Fuller = -3.7351, Lag order = 0, p-value = 0.02394
alternative hypothesis: stationary
But surprisingly it leads towards rejestion of NULL [p-value i...
2006 Jul 06
2
KPSS test
Hi,
Am I interpreting the results properly? Are my conclusions correct?
> KPSS.test(df)
---- ----
KPSS test
---- ----
Null hypotheses: Level stationarity and stationarity around a linear trend.
Alternative hypothesis: Unit root.
----
Statistic for the null hypothesis of
level stationarity: 1.089
Critical values:
0.10 0.05 0.025 0.01
0.347 0.463 0.574 0.739
----
Statistic for the null hypothesis of
trend stationarity: 0....
2002 Apr 03
3
non-stationary covariance
Hi !
Sorry for my ignorance. I have two questions:
1) which is in R the function to make a covariogram of spatial data ?
2) does anyone know if there exist the possibility in R of performing
kriging with an arbitrary covariance function ?
If I have well understood the Krig procedure offers only three
possibilities (expcov, gauscov and sphercov) that are the common models
for stationary and
2006 Feb 15
1
Generating random walks
Hello, here is another question, how do I generate
random walk models in R? Basically, I need an AR(1)
model with the phi^1 value equal to 1:
Yt = c + Yt-1 + E
where E is random white noise.
I tried using the arima.sim command:
arima.sim(list(ar=c(1)), n = 1000, rand.gen = rnorm)
but got this error since the model I am generating is
not stationary:
Error in arima.sim(list(ar = c(1)), n =
2010 Feb 17
0
adf.test help
Hi,
I am trying to test whether a series is return series stationary, but
before proceeding I wanted to make sure I understand correctly how to
use the adf.test function and interpret its output... Could you please
let me know whether I am correct in my interpretations?
ex: I take x such as I know it doesn't have a unit root, and is
therefore stationary
1/
> x <- rnorm(1000)
>
2013 Apr 30
1
ADF test --time series
Hi all,
I was running the adf test in R.
CODE 1:
adf.test(data$LOSS)
Augmented Dickey-Fuller Test
data: data$LOSS
Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775
alternative hypothesis: stationary
CODE 2:
adf.test(diff(diff(data$LOSS)))
Augmented Dickey-Fuller Test
data: diff(diff(data$LOSS))
Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01
alternative
2004 Nov 30
1
lme in R-2.0.0: Problem with lmeControl
Hello!
One note/question hier about specification of control-parameters in the
lme(...,control=list(...)) function call:
i tried to specify tne number of iteration needed via
lme(....,control=list(maxIter=..., niterEM=...,msVerbose=TRUE))
but every time i change the defualt values maxIter (e.g. maxIter=1,
niterEM=0) on ones specified by me, the call returns all the iterations
needed until
2009 May 03
0
QUADRATIC TREND FOR LINK FUNCTIONS ON NON-STATIONARY GEV
Hi All,
I am a newcomer to R. Could anyone explain me how to define link functions
for either mu/sigma to allow for quadratic trends in the same, when fitting
non-stationary GEV distributions?
Thanks
--
View this message in context: http://www.nabble.com/QUADRATIC-TREND-FOR-LINK-FUNCTIONS-ON-NON-STATIONARY-GEV-tp23360751p23360751.html
Sent from the R help mailing list archive at Nabble.com.
2006 May 11
1
Simulating scalar-valued stationary Gaussian processes
Hi,
I have a sample of size 100 from a function in interval [0,1] which can be
assumed to come from a scalar-valued stationary Gaussian process. There are
about 500 observation points in the interval. I need an effective and fast
way to simulate from the Gaussian process conditioned on the available data.
I can of course estimate the mean and 500x500 covariance matrix from data.
I have searched
2005 May 02
1
Trying to understand kpss.test() in tseries package
...quot;Trend"? The (condensed)
output from kpss.test() for the two possible null hypotheses is given
below. I don't see any significant difference between these results.
> x <- rnorm(1000) # is level stationary
> kpss.test(x, null="Level")
KPSS Test for Level Stationarity
KPSS Level = 0.0638, Truncation lag parameter = 7, p-value = 0.1
Warning: p-value greater than printed p-value
> kpss.test(x, null="Trend")
KPSS Test for Trend Stationarity
KPSS Trend = 0.0275, Truncation lag parameter = 7, p-value = 0.1
Warning: p-value greater than print...
2010 Oct 25
0
non-stationary ar part in css
...o find the starting values and then ML (as described on the
help page).
Now using the default may lead to error messages saying: "non-stationary
ar part in CSS". When changeing the default to "ML" only the
minimization works. As far as I understand, arima doesn't require
stationarity, but apparently CSS does.
Can anyone tell me what exactly the css method does? And why is CSS-ML
the default in R? Out of efficiency reasons? Because ML and ML-CSS gives
the exact same estimates when applied to the same data. I tried to find
out on google but I couldnt' find anything usefu...
2012 Aug 23
0
QUADRATIC LINK FUNCTIONS FOR MLE ESTIMATE OF NON-STATIONARY GEV FITS
Hi All,
I am a newcomer to S/R. Could you please let me know how to model quadratic
trends for the mul/sigl link functions when fitting non-stationary GEV
distributions using the ismev package?
Thanks
Best Regards,
Mohammad Ashrafuz Zaman
PhD Candidate
School of Engineering
Building XC, Room 1.02 (Kingswood Campus)
University of Western Sydney
Locked Bag 1797, Penrith South DC
NSW 1797
2012 Sep 17
2
Problem with Stationary Bootstrap
Dear R experts,
I'm running the following stationary bootstrap programming to find the parameters estimate of a linear model:
X<-runif(10,0,10)
Y<-2+3*X
a<-data.frame(X,Y)
coef<-function(fit){
fit <- lm(Y~X,data=a)
return(coef(fit))
}
result<- tsboot(a,statistic=coef(fit),R = 10,n.sim = NROW(a),sim = "geom",orig.t = TRUE)
Unfortunately, I got this
2004 Oct 13
4
incomplete function output
Dear R users,
I have a function (below) which encompasses several tests.
However, when I run it, only the output of the last test is
displayed. How can I ensure that the function root(var)
will run and display the output from all tests, and not
just the last one?
Thank you,
b.
root <- function(var)
{
#---Phillips-Perron
PP.test(var, lshort = TRUE)
PP.test(var, lshort = FALSE)
2009 Jan 23
1
forecasting error?
Hello everybody!
I have an ARIMA model for a time series. This model was obtained through an
auto.arima function. The resulting model is a ARIMA(2,1,4)(2,0,1)[12] with
drift (my time series has monthly data). Then I perform a 12-step ahead
forecast to the cited model... so far so good... but when I look the plot of
my forecast I see that the result is really far from the behavior of my time
2006 Feb 06
1
marginal distribution wrt time of time series ?
Dear all,
In many papers regarding time series analysis
of acquired data, the authors analyze 'marginal
distribution' (i.e. marginal with respect to time)
of their data by for example checking
'cdf heavy tail' hypothesis.
For i.i.d data this is ok, but what if samples are
correlated, nonstationary etc.?
Are there limit theorems which for example allow
us to claim that