Displaying 3 results from an estimated 3 matches for "state_match".
Did you mean:
state_fetch
2011 Jun 14
1
Invalid Regular Expression
...0 0 1
So basically, I'm generating a 1 if a phrase contains a state, city, or zip
code, and 0 if it doesn't.
Using the stringr package, I developed the following code:
library(stringr)
inscompany_match <- str_c(inscompany, collapse = "|")
state_match <- str_c(state, collapse = "|")
city_match <- str_c(city, collapse = "|")
agency_match <- str_c(agency, collapse = "|")
zipcode_match <- str_c(zipcode, collapse = "|")
mydf$inscompany <- as.numeric(str_detect(mydf$keyword, inscompany_match)...
2011 Jun 09
1
Error: missing values where TRUE/FALSE needed
...d28, d29,
d30, d31, d32, d33, d34, d35, d36, d37, d38, d39, d40, d41, d42, d43,
d44, d45, d46, d47, d48, d49, d50, d51, d52, d53, d54, d55, d56, d57,
d58, d59, d60, d61, d62, d63, d64, d65, d66, d67, d68, d69, d70)
library(stringr)
inscompany_match <- str_c(inscompany, collapse = "|")
state_match <- str_c(state, collapse = "|")
city_match <- str_c(city, collapse = "|")
mydf$inscompany <- as.numeric(str_detect(mydf$keyword, inscompany_match))
mydf$state <- as.numeric(str_detect(mydf$keyword, state_match))
mydf$city <- as.numeric(str_detect(mydf$keyword, cit...
2011 Jun 09
2
Problem with a if statement inside a function
...36, d37, d38, d39, d40, d41, d42,
d43,
d44, d45, d46, d47, d48, d49, d50, d51, d52, d53, d54, d55, d56,
d57,
d58, d59, d60, d61, d62, d63, d64, d65, d66, d67, d68, d69, d70)
library(stringr)
inscompany_match <- str_c(inscompany, collapse = "|")
state_match <- str_c(state, collapse = "|")
city_match <- str_c(city, collapse = "|")
mydf$inscompany <- as.numeric(str_detect(mydf$keyword,
inscompany_match))
mydf$state <- as.numeric(str_detect(mydf$keyword, state_match))
mydf$city <- as.numeric(str_...