search for: staggeringly

Displaying 20 results from an estimated 160 matches for "staggeringly".

Did you mean: staggering
2015 Apr 21
3
How to stagger fsck executions
From: Mark Milhollan Sent: April 21, 2015 05:35 > On Mon, 20 Apr 2015, Hugh E Cruickshank wrote: > > >CentOS 6 > > >From ''man fstab'' ... > > The sixth field, (fs_passno), is used by the fsck(8) > program to determine the order > in which filesystem checks are done at reboot time. > The root filesystem should be >
2015 Apr 21
0
How to stagger fsck executions
On 04/21/2015 06:08 AM, Hugh E Cruickshank wrote: > CentOS 6 > > Hi All: > > Over the weekend I had to reboot one of my systems and got hit with > fsck runs on all of the filesystems. I would not mind so much except > doing them all at once took over an hour. I would like to be able to > stagger these, ideally only execute one fsck per reboot. I have been > able to
2015 Apr 21
0
How to stagger fsck executions
On Tue, Apr 21, 2015 at 11:01 AM, Hugh E Cruickshank <hugh at forsoft.com> wrote: > > > Thanks but changing the order of execution or executing them in > parallel does not help with executing them one per reboot. Why do you care about running them at the same time when it doesn't take longer to run them all in parallel? Except I think the root filesystem normally runs
2015 Apr 21
0
How to stagger fsck executions
On Tue, Apr 21, 2015 at 11:40 AM, Hugh E Cruickshank <hugh at forsoft.com> wrote: > From: Les Mikesell Sent: April 21, 2015 09:19 >> >> Why do you care about running them at the same time when it doesn't >> take longer to run them all in parallel? Except I think the root >> filesystem normally runs first. So you might want to stagger it vs. >>
2015 Apr 21
7
How to stagger fsck executions
CentOS 6 Hi All: Over the weekend I had to reboot one of my systems and got hit with fsck runs on all of the filesystems. I would not mind so much except doing them all at once took over an hour. I would like to be able to stagger these, ideally only execute one fsck per reboot. I have been able to think of two possible solutions but neither is terrific. My first idea was to manually run fsck
2015 Apr 21
4
How to stagger fsck executions
From: Les Mikesell Sent: April 21, 2015 09:19 > > Why do you care about running them at the same time when it doesn't > take longer to run them all in parallel? Except I think the root > filesystem normally runs first. So you might want to stagger it vs. > everything else. I am trying to avoid running them at the same time in an effort to avoid 70 minute boot times (which is
2015 Apr 21
0
How to stagger fsck executions
On Tue, Apr 21, 2015 at 9:38 AM, Hugh E Cruickshank <hugh at forsoft.com> wrote: > CentOS 6 > > > My first idea was to manually run fsck on each filesystem, one every > couple of weeks. That way they will not all come due at the same time > if we reboot on a regular basis. > > The second idea was to set each filesystem to a different random count > value. This
2015 Apr 21
0
How to stagger fsck executions
On 4/20/2015 9:08 PM, Hugh E Cruickshank wrote: > The second idea was to set each filesystem to a different random count > value. This would run the risk of having two or more executions at > the same time but it would probably not be very frequent. > > Does anyone have a suggestion for a better way of doing this? use XFS, no fsck's until/unless something catastrophic happens
2015 Apr 21
0
How to stagger fsck executions
On 04/21/2015 09:40 AM, Hugh E Cruickshank wrote: > I accept that fscks are required on a periodic basis and I am willing > to reboot more often to achieve these but I would like to minimize > downtime (during the reboot) where possible. Why do you accept that? The default behavior for filesystems set up by Red Hat tools (anaconda) is not to fsck. Not by mount count, nor by time.
2015 Apr 21
0
How to stagger fsck executions
On Apr 21, 2015, at 9:50 AM, Hugh E Cruickshank <hugh at forsoft.com> wrote: > > From: Kay Diederichs Sent: April 21, 2015 03:43 >> >> instead of having 20 for all of them, set >> the first filesystem to 17, the second to 19, the third to 23, and the >> fourth to 29. > > Thanks but that is not much different then my second idea and does not > fully
2015 Apr 23
0
How to stagger fsck executions
On Apr 22, 2015, at 11:56 AM, Hugh E Cruickshank <hugh at forsoft.com> wrote: > > I have done some "what if" testing. Using which tool? My simulator, or something you cooked up yourself? If the latter, would you care to share? I?ve updated mine to break out the stats for 3+ volumes instead of just reporting all multi-volume fscks together:
2015 Apr 23
1
How to stagger fsck executions
From: Warren Young Sent: April 22, 2015 20:46 > On Apr 22, 2015, at 11:56 AM, Hugh E Cruickshank > <hugh at forsoft.com> wrote: > > > > I have done some "what if" testing. > > Using which tool? My simulator, or something you cooked up > yourself? If the latter, would you care to share? I cobbled something together in OpenEdge ABL. I have uploaded
2015 Apr 22
2
How to stagger fsck executions
From: Warren Young Sent: April 21, 2015 14:13 > On Apr 21, 2015, at 9:50 AM, Hugh E Cruickshank wrote: > > > > From: Kay Diederichs Sent: April 21, 2015 03:43 > >> > >> instead of having 20 for all of them, set > >> the first filesystem to 17, the second to 19, the third to > 23, and the > >> fourth to 29. > > > > Thanks but
2015 Apr 21
3
How to stagger fsck executions
From: Kay Diederichs Sent: April 21, 2015 03:43 > On 04/21/2015 06:08 AM, Hugh E Cruickshank wrote: > > > > The second idea was to set each filesystem to a different random > > count value. This would run the risk of having two or more > > executions at the same time but it would probably not be very > > frequent. > > Using "tune2fs -c", set the
2015 Apr 21
2
How to stagger fsck executions
From: Gordon Messmer Sent: April 21, 2015 10:30 > > On 04/21/2015 09:40 AM, Hugh E Cruickshank wrote: > > I accept that fscks are required on a periodic basis and I > am willing > > to reboot more often to achieve these but I would like to minimize > > downtime (during the reboot) where possible. > > Why do you accept that? Every article I have read on the
2014 Nov 24
2
[LLVMdev] Heads up! Planning to remove old vector shuffle lowering this week...
I'll be skimming the PRs to see if there are any really critical regressions, but so far it looks pretty good. If you are actively disabling the new vector shuffling and have some PR that blocks you, please reply here. Later this week, the flag will go away unless I hear strenuous objections. There is a really staggering amount of cleanup and tidying that needs to take place and can't
2011 Mar 15
1
Using stride on non-RAID
Hello, I understand the need for a proper stride setting when formatting a filesystem on a RAID device. However, is there any problem in using a stride setting when formatting a filesystem on a regular non-RAID, non-SSD, just plain-vanilla-single-disk block device? I'm sure there isn't any benefit to it, but I'm curious if there is any harm. The reason I ask is I'm looking at
2007 Sep 28
2
plot graph with error bars trouble
Hi, I have a data set like this: Mutant Rep Time OD 02H02 1 0 0.029 02H02 2 0 0.029 02H02 3 0 0.023 02H02 1 8 0.655 02H02 2 8 0.615 02H02 3 8 0.557 02H02 1 12 1.776 02H02 2 12 1.859 02H02 3 12 1.668 02H02 1 16 3.379 02H02 2 16 3.726 02H02 3 16 3.367 306 1 0 0.033 306 2
2006 Mar 21
7
Rails and JRuby
Has anyone attempted to run Rails inside of JRuby? Is that even possible? Aside from the performance implications, is it a bad idea? I''m thinking that it might be useful in very rare cases where a Ruby/Rails - equivalent of a Java solution may not exist yet. Any thoughts? Wes -- Posted via http://www.ruby-forum.com/.
2013 Feb 25
3
How to plot 2 continous variables on double y-axis with 2 factors: ggplot2, gplot, lattice, sciplot?
Hi, I have a data set with two continous variables that I want to plot MEANS (I am not intrerested in median values) on a double-y graph. I also have 2 factors. I want the factor combinations plotted in different panes. Dummy dataset: mydata <- data.frame(factor1 = factor(rep(LETTERS[1:3], each = 40)), factor2 = factor(rep(c(1:4), each = 10)), y1 =