Displaying 4 results from an estimated 4 matches for "sstot".
Did you mean:
sslot
2004 Sep 30
1
function by
Hi,
I'm just getting started with R and I'm having problems with some simple
operations: I want to get the the sum of the column "SStot" for each year using
the function by. The data set is named "SS". I've tried this:
by (SS, year, sum(SStot))
and it's not working. Is it because there's a different number of rows for each
year? How else can I do this?
--
Emilie Berthiaume
Graduate student
Biology...
2005 Sep 08
0
Effect of data set size on calculation
...n below:
# ANOVA 2D GC analysis
# maxc <- number of samples
# nreps <- number of samples
maxc <- 2
nreps <- 4
sscl <- NULL
cmean <- NULL
#
# Initial stat. variable
#
dftot <- nrow(mat)-1
dfcl <- maxc - 1
dferr <- dftot - dfcl
totmean <- mean(mat)
sstot <- sd(mat)^2*dftot
#
# Calculate class-to-class variance
#
for (j in 1:maxc) {
cmean <- rbind(cmean,mean(mat[((j-1)*nreps+1):((j-1)*nreps+nreps),]))
}
for (j in 1:ncol(mat)) {
cmean[,j] <- cmean[,j]-totmean[j]
}
cmean <- (cmean)^2*nreps
for (i in 1:ncol(mat)) {
sscl[i] &...
2011 Feb 21
0
r-square for cluster
...ic for a given clustering solution. In fact, I have different cluster solution for a given set of data. I would like to know which cluster solution gives the highest R2. My data (5 variables) are scaled to a 0 mean and 1 std. This is the command lines I used to calculate R2 for 1 cluster solution:
SSTot <- (nrow(grid40km.datascale)-1)*sum(apply(grid40km.datascale,2,var)) # total sum of square
SStot_grid40km <- NULL
for (i in 1:22) # there is 22 clusters
{
data_group <- subset(grid40km.data,grid40km.cluster==i, select=c(X1, X2, X3, X4, X5))
SSgroup <- (nrow(data_group-1)*sum(apply(dat...
2011 Feb 27
1
two-way unbalanced ANOVA
Hello Everyone,
*Question: *How do you calculate the sum of squares for a two-way
_unbalanced_ ANOVA?
*What I have done:*
I have found many useful tutorials online for running a balanced two-way
ANOVA but I haven't had much luck for running a unbalanced two-way
ANOVA. From what I have read, the trouble with running an unbalanced
two-way ANOVA, is that things get tricky when calculating