search for: ssefick

...probably due to my incomplete understanding of grep, but the below code has been working for some time to #search for .R with anything in front of it and return a list of scripts to source. Likely, the syntax for the #grep statement has been wrong all along. scripts2source <- (c("/home/ssefick/R_scripts/Convert_package.R", "/home/ssefick/R_scripts/Convert_R_CODE", "/home/ssefick/R_scripts/CV.R", "/home/ssefick/R_scripts/cvs.out.R", "/home/ssefick/R_scripts/database_connect", "/home/ssefick/R_scripts/database_connect_package.R", &qu...

...lude/ut_type.h:18, from ../inst/include/fra_dim.h:9, from RS_fra_dim.c:20: /usr/include/bits/endian.h:27:4: error: #error Both BIG_ENDIAN and LITTLE_ENDIAN defined! make: *** [RS_fra_dim.o] Error 1 ERROR: compilation failed for package ?ifultools? * Removing ?/home/ssefick/ifultools.Rcheck/ifultools? -- Stephen Sefick Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are mammals, and have not exhausted the annoying little problems of being mam...

Hi everyone, > does any one knows how can I calculate mean for different samples > i.e. I have a data like this: > > s1 s2 s3 s4 > 1 0 0 0 1 > 2 1 0 1 0 > 3 0 0 0 0 > 4 0 0 0 0 > 5 0 1 0 1 > 6 1 0 0 0 > 7 0 0 0 0 > 8 0 0 0 0 > 9 0 0 0 0 > 10 0 0 0 1 > > I need to make 5 different sample with 5

These are date and times in the format YYYYMMDDhhmmss. I would like to take this column and make a chron object form them. I have tried a couple of the split family of functions but they need character input here is the data: date.time <- c(19851001001500, 19851001003000, 19851001004500, 19851001010000, 19851001011500, 19851001013000, 19851001014500, 19851001020000, 19851001021500,

#copy and paste this into R f <- (structure(list(TKN = c(0.103011025, 0.018633208, 0.104235702, 0.074537363, 0.138286096), RM = c(215, 198, 148, 119, 61)), .Names = c("TKN", "RM"), class = "data.frame", row.names = 25:29)) plot(f$TKN~f$RM, type="b") I would like to reverse the X-Axis. How do I do this? -- Let's not spend our time and resources

.../include -fpic -g -O2 -c surfaceArea.c -o surfaceArea.o gcc -std=gnu99 -I/usr/share/R/include -fpic -g -O2 -c zerodist.c -o zerodist.o gcc -std=gnu99 -shared -o sp.so Rcentroid.o gcdist.o init.o pip.o pip2.o sp_xports.o surfaceArea.o zerodist.o -L/usr/lib64/R/lib -lR installing to /home/ssefick/R/x86_64-pc-linux-gnu-library/2.11/sp/libs ** R ** data ** demo ** inst ** preparing package for lazy loading Error: package ?sp? is required by ?maptools? so will not be detached * removing ?/home/ssefick/R/x86_64-pc-linux-gnu-library/2.11/sp? * restoring previous ?/home/ssefick/R/x86_64-pc-linux-...

station month bas 190 5 0.000 190 7 1.563 190 10 0.000 190 11 0.000 202 4 18.750 202 5 18.750 202 7 6.250 202 10 4.800 202 11 3.125 198 4 18.750 198 5 31.250 198 7 3.125 198 10 3.200 198 11 12.500 205 4 0.000 205 5 0.000 205 7 0.000

...so and suggested windows binaries and I must confess I was only familiar with installing from files via the package sources (apart from the conventional install.packages method), so the solution was as simple as installing via the binaries. Thanks again, best wishes, James From: stephen sefick <ssefick at gmail.com> Sent: Wednesday 21 February 2024 12:25 To: James Powell <James.Powell at hse.ie> Cc: r-help at r-project.org Subject: Re: [R] Network issue CAUTION: This email originated from outside of the organisation. Do not click links or open attachments unless you recognise the sender...

I would like to reformat this data frame into something that I can produce some descriptive statistics. I have been playing around with the reshape package and maybe this is not the best way to proceed. I would like to use RiverMile and constituent as the grouping variables to get the summary statistics: 198a 198b mean mean sd sd ... ... etc. for all of these. I have tried

RM215.sp <- SpatialPoints(RM215, proj4string=CRS("+proj=longlat +datum=WGS84")) d060101 <- as.POSIXct("2006-01-01", tz="EST") study_seq <- seq(from=d060101, length.out=761, by="days") up.215 <- sunriset(RM215.sp, study_seq, direction="sunrise", POSIXct.out=TRUE) down.215 <- sunriset(RM215.sp, study_seq, direction="sunset",

plot(1,2, ylab= paste("insects", expression(m^2), sep=" ")) I get insects m^2 I would like m to the 2 what is the problem? -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are mammals, and have not exhausted the annoying little problems of being

I am using the function metaMDS with jaccard distances to ordinate a set of constituent by site matrix. I can post this data if it would be helpful, but it is large to include in an email. I can also provide reproducable code if necessary. I would like to get an R^2 value for the axes of the ordination configuration that I get with metaMDS in the vegan package is there a way to do this- is it

below is my data frame. I would like to compute summary statistics for mgl for each river mile (mean, median, mode). My apologies in advance- I would like to get something like the SAS print out of PROC Univariate. I have performed an ANOVA and a tukey LSD and I would just like the summary statistics. thanks stephen RM mgl 1 215 0.9285714 2 215 0.7352941 3 215 1.6455696 4 215

Does anyone know of a test for stationarity of a time series, or like all ordination techniques it is a qualitative assessment of a quantitative result. Books, papers, etc. suggestions welcome. thanks Stephen -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are

#I am putting a test together for an introductory biology class and I would like to put different cross hatching inside of each bar for the bar plot below color <- c("Brightly Colored", "Dull", "Neither") lizards <- c(277, 70, 3) liz.col <- data.frame(color, lizards) qplot(color, lizards, data=liz.col, geom="bar", ylab="Observed Matings",

Is there any easy way to pull out the row indexes for a logical matching statment? #################example code######################################### foo <- data.frame(name=c(rep("A", 25), rep("B", 25), rep("C", 25), rep("A", 25)), stuff=rnorm(100), and=rnorm(100), things=rnorm(100)) #this is what I want but I would like the row indexes

#this is my little function that I would like to use the column names of the x and y arguments in the function. I would like it to read # site1-site2 how would I do this diff.temp <- function(x, y ,use="pairwise.complete.obs") { na.method <- pmatch(use, c("all.obs", "complete.obs", "pairwise.complete.obs")) par(mfrow=c(2,1))

Hello, When I put in the following script line: gap.boxplot(CLI3, CLI4, CLI5, CLI6, CLI7, gap=list(top=c(8000,280000), bottom=c(0,250)), range=50, outline=TRUE, par(ask=FALSE) I get a '+' telling me I am missing something. I have tried adding ')', 'width=NULL', etc and then I get this error: Error: unexpected symbol in: "gap.boxplot(CLI3, CLI4, CLI5, CLI6, CLI7,

?for doesn't return anything help.search("for") doesn't return anything- Is the for loop so prevelant in computer programing that the documentation is implicit or is R paradigm to discourage the use of the for loop. I will post data probably tonight, but here is my problem. I have preformed an MDS on a set of data. I have the scores of the four axes that are the optimal

Hi, I would like to know how can I keep adding data to a file while doing a loop and without deleting the data of the previous iteration. Thanks.