Displaying 2 results from an estimated 2 matches for "spz8".
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pz8
2009 Mar 13
2
Taking diff of character vectors
Hello, everybody
Say I have
nm1 <- c(rep(1,10), rep(0,10))
then I can do:
diff(nm1)
to see where I have shift in value
but what if I have
nm2 <- c(rep("SPZ8", 10), rep("SPX9", 10))
how can I produce the same ouput as diff(nm1) does, that is zeros
everywhere except for one place where SPZ8 changes to SPX9 (there
should be 1 there)?
What if I have a matrix of characters like that:
nm3 <- c(rep("GLF9", 4), rep("GLF10&quo...
2009 Mar 14
1
multiple hypothesis testing
...; > Hi:
> > For A, you can use head and tail but you have to add a zero the front.
> > For B, you can use the same function, but put it inside an sapply and run
> > over the columns and then cbind it back with the original dataframe.
> > A)
> > nm2 <- c(rep("SPZ8", 10), rep("SPX9", 10))
> > -1.0*c(0,as.numeric((head(nm2,-1) != tail(nm2,-1))))
> >
> > B)
> > nm3 <- c(rep("GLF9", 4), rep("GLF10", 16))
> > matr <- cbind(nm2, nm3)
> > temp<-as.data.frame(sapply(1:ncol(matr), functio...