search for: speexfloat

...rame-sized (320 bytes) fragments. Since I deal only with char data types, I convert to 2-byte short values first and then set the float buffer. char *CSpeex::encode (char *buffer, int size, int &encodeSize) { char *encodedBuffer = new char[160]; short speexShort; float *speexFloat = new float[160]; // Convert the audio to a short then to a float buffer for (int i = 0; i < 160; i++) { memcpy(&speexShort, &buffer[i*2], sizeof(short)); speexFloat[i] = speexShort; } // Encode the sound data using the flo...

...eex codec for encoding the data so the encoding function is called (I am thankful to Tay YueWeng for the function). char *encode(char *buffer, int &encodeSize) { char *encodedBuffer = new char[RECBUFFER/2]; /* RECBUFFER = 2000 */ short speexShort; float speexFloat[RECBUFFER/2]; void *mEncode = speex_encoder_init(&speex_nb_mode); /*Initialization of the structure that holds the bits*/ speex_bits_init(&mBits); // Convert the audio to a short then to a float buffer int halfBufferSize = RECBUFFER/2; for (...

...4 beforehand and experienced the same problem with it. 1. I record my audio at mono 8000Hz, 16bits per sample. 2. I encode frame-sized (320 bytes) fragments. char *encode(char *buffer, int &encodeSize) { char *encodedBuffer = new char[160]; short speexShort; float *speexFloat = new float[160]; // Convert the audio to a short then to a float buffer for (int i = 0; i < 160; i++) { memcpy(&speexShort, &buffer[i*2], sizeof(short)); speexFloat[i] = speexShort; } // Encode the sound data using the...

...yte short values first and then set the >> float buffer. >> >> char *CSpeex::encode (char *buffer, int size, int &encodeSize) >> >> { >> >> char *encodedBuffer = new char[160]; >> >> short speexShort; >> >> float *speexFloat = new float[160]; >> >> >> >> // Convert the audio to a short then to a float buffer >> >> for (int i = 0; i < 160; i++) >> >> { >> >> memcpy(&speexShort, &buffer[i*2], sizeof(short)); >> >>...