search for: spec2

...occurrences into a presence-only table (3 columns) with the names of the species (1st column), the lat information of the sites (2nd column) and the lon information of the sites (3rd column), as given in the below example? Thanks a lot for your help! Christian my dataframe: site lat lon spec1 spec2 spec3 spec4 site1 10 11 1 0 1 0 site2 20 21 1 1 1 0 site3 30 31 0 1 1 1 my desired new dataframe: species lat lon spec1 10 11 spec1 20 21 spec2 20 21 spec2 30 31 spec3 10 11 spec3 20 21 spec3 30 31 spec4 30 31 -- Christian Hof, PhD student Center for Macroecology & Evolution University...

Hello, I would like to reshape a dataframe into an array. This is kind a similar task as Excel performs with a Pivot table. To illustrate it: LOC <- factor(c(1,2,2,3,1,1)) SPEC1 <- c(0,0,23,0,12,11) SPEC2 <- c(1,2,0,0,0,4) df <- data.frame(LOC,SPEC1,SPEC2) # original dataframe a <- array(NA,dim=c(length(levels(LOC)),1,2),dimnames=list(levels(LOC),"LOC",c("SPEC1","SPEC2"))) #new array set up, how it should look like The final array is splitted by the SPEC (fo...

dear R-friends, i`ve got a large dataset of vegetation-samples with about 500 variables(=species) in the following format: 1 spec1 1 spec23 1 spec54 1 spec63 2 spec1 2 spec2 2 spec253 2 spec300 2 spec423 3 spec20 3 spec88 3 spec121 3 spec200 3 spec450 . . this means: sample 1 (grassland) with the species (=spec) 1, 23, 54, 63 is it possible to get a following data-structure for further analysis? 1 2 3 ...... spec1 1 1 0 spec2...

...s an unexpected restriction: the compiler will not permit different speculations to be committed in the same instance of a probe identifier. For instance, consider the following useless D script: #!/usr/sbin/dtrace -s #pragma D option nspec=2 BEGIN { spec1 = speculation(); spec2 = speculation(); } END { commit(spec1); commit(spec2); } # ./spec.d dtrace: failed to compile script ./spec.d: line 12: commit( ) may not follow commit( ) However, if the script is changed to: #!/usr/sbin/dtrace -s #pragma D option nspec=2 BEGIN { spec1 =...

Hi, Can anyone pls help me in plotting the following data? The data-set contains company name, specification-1, specification-2. The graph would basically plot company name with specification-1 on x-axis, & specification-2 on y-axis. Simply put - company name should get classified into one of the four quardrants created by specification 1 & specification2. Thanks.

Hi R-helpers, I have a dataframe (called data) with trees in rows (n=100) and insect species (n=10) in columns. My tree IDs are in a column called TREE and each species has a column labeled SPEC1, SPEC2, SPEC3, etc... I wish to randomize the values in my dataframe such that row and column totals are held constant, i.e. in my randomized data each tree will have the same number of individual insects as in the real data (constant row totals) and each species will have the same number of individuals...

...s in the dataframe Y, species,,,, #where Y=number of columns in the dataframe ,Q,Q,Q,Q,Q #where the number of Qs=the number of columns in the dataframe Those 3 .csv header lines would be followed by dataframe, which consists of one row containing column headers and X "data" rows: ,spec1,spec2,spec3,sp3c4,spec5 #these are the dataframe's column headers plot1,15.84,0,0,792,7 #this is an example "data" row In case the above is unclear, I have also attached a small .csv as an example of what the output should look like. Thank you. Mark

I am really a beginner of PRI ISDN board, I am wondering if there is a "quick start" chan_dahdi.conf configuration I could use. I tried to install two "FreePBX" boxes follow the instructions from "http://www.cadvision.com/blanchas/Asterisk/DahdiT1trunk.html" connected them between PRIs, It worked. And now if I refer the FreePBX "chan_dahdi.conf" it looks

...~1 | Species (Intercept) StdDev: 2.937479 Formula: ~1 | Replicate %in% Species (Intercept) Residual StdDev: 4.973931 4.266302 Fixed effects: Max_speed ~ Species Value Std.Error DF t-value p-value (Intercept) 23.792040 4.798143 39 4.958593 0 Spec2 -7.121766 6.747930 0 -1.055400 NaN Spec3 -9.779830 6.725391 0 -1.454165 NaN So I get variance within species and within replicates, but what the hell are these zero DF's, leading to zero p's and how should I interpret them? Another model I tried was: mod2<-lme(Es...

...ircheck: 0 debug.nosleepwithlocks: 0 debug.mpsafevm: 1 debug.psm.loglevel: 0 debug.psm.hz: 20 debug.psm.errsecs: 2 debug.psm.errusecs: 0 debug.psm.secs: 0 debug.psm.usecs: 500000 debug.psm.pkterrthresh: 2 debug.fdc.fifo: 8 debug.fdc.debugflags: 0 debug.fdc.retries: 10 debug.fdc.spec1: 175 debug.fdc.spec2: 16 debug.fdc.settle: 0 debug.PMAP1changedcpu: 1 debug.PMAP1changed: 1622 debug.PMAP1unchanged: 162299 debug.acpi.do_powerstate: 1 debug.acpi.acpi_ca_version: 0x20041119 debug.acpi.semaphore_debug: 0 hw.machine: i386 hw.model: AMD Athlon(tm) 64 X2 Dual Core Processor 3800+ hw.ncpu: 2 hw.byteorder:...

...D:     <e40d78ce0907080854l243f9fd9h59e5accf2aeb47b6@mail.gmail..com> Content-Type: text/plain Hi R-helpers, I have a dataframe (called data) with trees in rows (n=100) and insect species (n=10) in columns. My tree IDs are in a column called TREE and each species has a column labeled SPEC1, SPEC2, SPEC3, etc... I wish to randomize the values in my dataframe such that row and column totals are held constant, i.e. in my randomized data each tree will have the same number of individual insects as in the real data (constant row totals) and each species will have the same number of individuals...