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movable
2007 Jun 19
1
Iterative Solver [Converting Matlab's solve()]
I can't for the life of me figure out how to get the roots for this simple
(but sovable only iteratively) equation in R:
x = z*(1-(1-2/z)^y
where x and y are known, and z is unknown. In Matlab, this amounts to:
[my.solution] = solve('x = z*(1-(1-2/z)^y')
my.solution.real = solution(y-1,y)
% bottom line displays non-imaginary solution (last element)
Obviously, I'm dee...