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source_dirname
2010 Jun 11
4
setting the current working directory to the location of the source file
...about it's own location.
I need this to make sure that the script will find its datafiles after I
move the whole directory. (The datafiles are in the same directory.)
Here is a hack I invented to work around it:
print(getwd())
source_pathname = get("ofile",envir = parent.frame())
source_dirname = dirname(source_pathname )
setwd(source_dirname)
print(getwd())
Question: Is there a better, cleaner way?
Thanks,
mrgomel
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