Displaying 1 result from an estimated 1 matches for "sortweath".
2011 Apr 11
0
joining data based upon a moving time window?
...4/10/2003 22:41:00 6.70 106.00 17661.00
4/10/2003 23:41:00 6.60 106.00 22000.00
4/10/2003 0:41:00 6.18 106.00 22000.00
4/11/2003 17:41:00 8.17 102.86 3462.43
4/12/2003 18:41:00 7.96 104.29 6541.0
#####code:
SortLoc = loc[order(loc$DateTime),] #sorting the location data
SortWeath = weather[order(weather$DateTime),] #sorting the weather data
####
weathrow =1
for (i in 1:nrow(SortLoc)) {
t = 0
while (t < 1){
timedif1 = difftime(SortLoc$DateTime[i], SortWeath$DateTime[weathrow],
units="auto")
timedif2 = difftime(SortLoc$DateTime[i],...