search for: sokovic

Displaying 12 results from an estimated 12 matches for "sokovic".

2020 Oct 09
3
2 D density plot interpretation and manipulating the data
...s. e.g. Remove the data points with the 20 lowest density values. Or remove the data points with the lowest 5% of density values. I'll let you decide whether that is a good idea or a bad idea. And if it's a good idea, then how much to trim. On Sat, Oct 10, 2020 at 5:47 AM Ana Marija <sokovic.anamarija at gmail.com> wrote: > > Hi Bert, > > Another confrontational response from you... > > You might have noticed that I use the word "outlier" carefully in this > post and only in relation to the plotted ellipses. I do not know the > underlying algorithm...
2020 Oct 09
0
2 D density plot interpretation and manipulating the data
...with the 20 lowest density values. > Or remove the data points with the lowest 5% of density values. > > I'll let you decide whether that is a good idea or a bad idea. > And if it's a good idea, then how much to trim. > > > On Sat, Oct 10, 2020 at 5:47 AM Ana Marija <sokovic.anamarija at gmail.com> wrote: > > > > Hi Bert, > > > > Another confrontational response from you... > > > > You might have noticed that I use the word "outlier" carefully in this > > post and only in relation to the plotted ellipses. I do not...
2020 Oct 09
2
2 D density plot interpretation and manipulating the data
...hat's why I believe you need local expertise. Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Fri, Oct 9, 2020 at 8:25 AM Ana Marija <sokovic.anamarija at gmail.com> wrote: > Hi Abby, > > thank you for getting back to me and for this useful information. > > I'm trying to detect the outliers in my distribution based of mean and > variance. Can I see that from the plot I provided? Would outliers be > outside of...
2020 Oct 09
0
2 D density plot interpretation and manipulating the data
...al expertise. > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along and sticking things into it." > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > On Fri, Oct 9, 2020 at 8:25 AM Ana Marija <sokovic.anamarija at gmail.com> wrote: >> >> Hi Abby, >> >> thank you for getting back to me and for this useful information. >> >> I'm trying to detect the outliers in my distribution based of mean and >> variance. Can I see that from the plot I provided? W...
2020 Oct 21
0
how do I remove entries in data frame from a vector
On Wed, 21 Oct 2020 16:15:22 -0500 Ana Marija <sokovic.anamarija at gmail.com> wrote: > Hello, > > I have a data frame with one column: > > > remove > > V1 > > 1 ABAFT_g_4RWG569_BI_SNP_A10_35096 > 2 ABAFT_g_4RWG569_BI_SNP_B12_35130 > 3 ABAFT_g_4RWG569_BI_SNP_E09_35088 > 4 AB...
2023 Jun 13
1
log transform a data frame
...; > Do not use printouts of your data since it hides important information. > Use str(a11) and dput(a11) or dput(head(a11)) to provide useful information > about your data. > > David L Carlson > Texas A&M University > > > On Tue, Jun 13, 2023 at 4:08?PM Ana Marija <sokovic.anamarija at gmail.com> > wrote: > >> Hello, I have a data frame like this: d11=suppressWarnings(read. >> csv("/Users/anamaria/Downloads/B1. csv", stringsAsFactors=FALSE, >> header=TRUE)) > d11 X Domain. decomp. DD. com. . load Neighbor. search >> Launc...
2020 Oct 21
4
how do I remove entries in data frame from a vector
Hello, I have a data frame with one column: > remove V1 1 ABAFT_g_4RWG569_BI_SNP_A10_35096 2 ABAFT_g_4RWG569_BI_SNP_B12_35130 3 ABAFT_g_4RWG569_BI_SNP_E09_35088 4 ABAFT_g_4RWG569_BI_SNP_E12_35136 5 ABAFT_g_4RWG569_BI_SNP_F11_35122 6 ABAFT_g_4RWG569_BI_SNP_F12_35138 7 ABAFT_g_4RWG569_BI_SNP_G07_35060 8 ABAFT_g_4RWG569_BI_SNP_G12_35140 I want to remove these 8
2020 Oct 09
0
2 D density plot interpretation and manipulating the data
...es/ggplot2-color-by-density/ and then do something like this: a=SNP[SNP$density>400,] and plot it again: p <- ggplot(a, mapping = aes(x = mean, y = var)) p <- p + geom_density_2d() + geom_point() + my.theme + ggtitle("SNPS_red") On Thu, Oct 8, 2020 at 3:52 PM Ana Marija <sokovic.anamarija at gmail.com> wrote: > > Hello, > > I have a data frame like this: > > > head(SNP) > mean var sd > FQC.10090295 0.0327 0.002678 0.0517 > FQC.10119363 0.0220 0.000978 0.0313 > FQC.10132112 0.0275 0.002088 0.0457 > FQC.10201128...
2020 Oct 08
2
2 D density plot interpretation and manipulating the data
Hello, I have a data frame like this: > head(SNP) mean var sd FQC.10090295 0.0327 0.002678 0.0517 FQC.10119363 0.0220 0.000978 0.0313 FQC.10132112 0.0275 0.002088 0.0457 FQC.10201128 0.0169 0.000289 0.0170 FQC.10208432 0.0443 0.004081 0.0639 FQC.10218466 0.0116 0.000131 0.0115 ... and I am creating plot like this: s <- ggplot(SNP, mapping = aes(x = mean, y = var))
2023 Jun 13
1
log transform a data frame
Hello, I have a data frame like this: d11=suppressWarnings(read.csv("/Users/anamaria/Downloads/B1.csv", stringsAsFactors=FALSE, header=TRUE)) > d11 X Domain.decomp. DD.com..load Neighbor.search Launch.PP.GPU.ops. Comm..coord. 1 SYCL 2. 1 0 3.7 0. 1 1 .6 2 CUDA 2 0 3. 1 0 1 .0
2020 Oct 09
0
2 D density plot interpretation and manipulating the data
Hi Abby, thank you for getting back to me and for this useful information. I'm trying to detect the outliers in my distribution based of mean and variance. Can I see that from the plot I provided? Would outliers be outside of ellipses? If so how do I extract those from my data frame, based on which parameter? So I am trying to connect outliers based on what the plot is showing: s <-
2020 Oct 09
2
2 D density plot interpretation and manipulating the data
> My understanding is that this represents bivariate normal > approximation of the data which uses the kernel density function to > test for inclusion within a level set. (please correct me) You can fit a bivariate normal distribution by computing five parameters. Two means, two standard deviations (or two variances) and one correlation (or covariance) coefficient. The bivariate normal