Displaying 6 results from an estimated 6 matches for "soep".
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2000 Aug 21
2
Loop removal possible?
...he beginning position
for (i in 1:length(w)) {# <<- this loop i want to remove ??
k[i] <- sum(a[i]:e[i])
}
return(k)
}
for the example the function calculate:
> hilf.w(w)
[1] 3 3 15 15
Thanks a lot in advance for any suggestions,
Jan Goebel (jgoebel at diw.de)
DIW Berlin
SOEP
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2000 Nov 09
3
maximum of nsize=20000k ??
Dear R-ers,
somehow it is not possible to increase nsize to more than
20000k. When I specify e.g.
> R --vsize=10M --nsize=21000K
the result is:
free total (Mb)
Ncells 99658 350000 6.7
Vcells 1219173 1310720 10.0
Maybe I have overlooked s.th....
Marcus
--
+-------------------------------------------------------
| Marcus Eger
| E-Mail: eger.m at gmx.de (NEW)
|
2000 Oct 17
3
Cleaning things up?
Hi,
I know it must be written somewhere but I can't find it.
I'd like to remove all variables or objects that I've created but not the
functions. I look at a few things without success. Is there a R way of doing
this? There are to many to create a manual list.
Thanks in advance.
Yves Gauvreau
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r-help
2000 Oct 11
5
"Executing" a string
In Matlab or Octave I can evaluate (evalf) the content of
a string. In R I have looked around in the docs, but have not
found a way to do something equivalent (which is possible, I think).
Can anybody give me a pointer?
=============================================================================
Thomas Hoffmann, Institut fuer Halbleiter- und Mikrosystemtechnik, TU Dresden
E-mail: hoffmann at
2000 Oct 23
3
behaviour of plot(...,type="l")
plot(rnorm(100000),type="l")
plots only about 7e4 lines while the same without type="l" works fine.
Is this a feature or a bug or is this configurable?
R : Copyright 2000, The R Development Core Team
Version 1.1.1 (August 15, 2000)
SunOS 5.5.1 Generic_103640-29 sun4u sparc SUNW,Ultra-1
Thanks
Adrian
--
Adrian Trapletti, Olsen & Associates Ltd., See-
feldstrasse
2000 Aug 29
4
short way
i want to replace certain values of a matrix.
i know how to replace them when the values are in a vector.
i tried the same way for a matrix and got this answer:
la[la==0]<-1
Error in [<-.data.frame(*tmp*, la == 0, value = 1) :
matrix subscripts not allowed in replacement
i found a way to do this with "for()",
but i think this is the worst way to do it.
So is there a